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2 years ago

Please tell me I’ll give you Brinley

Mathematics

1 answer:

babymother [125]2 years ago

8 0

Answer:

i was thinking B or D

Step-by-step explanation:

and yes i can read the answers at the bottom

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The volumes of two similar solids are 125 cm^3 and 1,000 cm^3. The surface area of the smaller solid is 150 cm^2. What is the su

Flura [38]

<u>Find scale Factor:</u>

$(\cfrac{length_1}{length_2})^3 = \cfrac{volume_1}{volume_2}$

$(\cfrac{length_1}{length_2})^3 = (\cfrac{125}{1000} )$

$\cfrac{length_1}{length_2} = \sqrt[3]{\cfrac{125}{1000} }$

$\cfrac{length_1}{length_2} = \cfrac{5}{10} = \cfrac{1}{2}$

<u>Find Surface area of the larger solid:
</u>

$(\cfrac{length_1}{length_2} )^ 2=\cfrac{area_1}{area_2}$

$(\cfrac{1}{2} )^ 2=\cfrac{150}{area_2}$

$\cfrac{1}{4} =\cfrac{150}{area_2}$

$area_2 = 150 \times 4 = 600 \text{ cm}^2$

Answer: 600 cm²

3 0

3 years ago

What is the answer to 4819 / 68<br>

Drupady [299]

Answer:

= 70.8676471

Step-by-step explanation:

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3 years ago

Read 2 more answers

Fill in the blank.<br> 5x(2 + 10) = (5x__) + (5 x 10)

shtirl [24]

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3 years ago

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Evaluate each expression for a = -4, b = 3, and c = 2.<br> 4a²b-23

aleksklad [387]

Answer: -215

Please give brainliest

4 0

3 years ago

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0

2 years ago