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Rufina [12.5K]
4 years ago
5

If lim f(x) = 5, lim g(x) = 0, and lim h(x) = -2, then find lim g/h (x)

Mathematics
2 answers:
NeTakaya4 years ago
6 0

Answer:

C) 3

Step-by-step explanation:

JUST ANSWER IT

Anuta_ua [19.1K]4 years ago
5 0

We have been given that \lim_{x \to a} f(x)=5, \lim_{x \to a} g(x)=0 and \lim_{x \to a} h(x)=-2. We are asked to find the \lim_{x \to a} \frac{g}{h}(x).

We will use limit rules to solve our given problem.

\lim_{x \to a} \frac{g}{h}(x)=\lim_{x \to a} \frac{g(x)}{h(x)}= \frac{\lim_{x \to a}g(x)}{\lim_{x \to a}h(x)}

Upon substituting our given values in above formula, we will get:

\frac{\lim_{x \to a}g(x)}{\lim_{x \to a}h(x)}=\frac{0}{-2}

\frac{\lim_{x \to a}g(x)}{\lim_{x \to a}h(x)}=0

Therefore,  \lim_{x \to a} \frac{g}{h}(x) is 0 and option C is the correct choice.

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Like charges repel and I like charges attract Coulomb’s law states that the force F of attraction or repulsion between two charg
olga_2 [115]

Step-by-step explanation:

For the charges that have same sign of charges will repel each other while for the charges that have different charges will attract each other. So, we can say that like charges repel and unlike charges attract each other.

The Coulomb's law of attraction of repulsion states that force between charges is directly proportion to the product of charges and inversely proportional to the square of distance between them. Mathematically, it is given by :

F=\dfrac{kq_1q_2}{r^2}

Hence, all the given statements are true.

8 0
3 years ago
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
3 years ago
A hotel has $504 to buy new pillows. If the cost of each pillow is $6, how many pillows will the hotel be able to buy? A) 78 B)
Naddik [55]
Hello there! 
You can use the equation:
504 ÷ 6
84
The hotel can buy 84 pillows.
Hope this helped! :D

4 0
3 years ago
Read 2 more answers
Simplify these expressions.<br> a. 4x + 7x + (–x)<br> b. –5yz + yz + 2yz
salantis [7]

Answer:A. 10x. B. -2yz

Step-by-step explanation:

A. 4x+7x=11x

11x+(-x) = 11x-1x=10x

B. -5yz+yz=-4yz

-4yz+2yz=-2yz

4 0
3 years ago
What is 12 2/3 as an improper fraction
BaLLatris [955]

Answer:

\dfrac{38}{3}

Step-by-step explanation:

12\dfrac{2}{3} =

= 12 + \dfrac{2}{3}

= \dfrac{12}{1} + \dfrac{2}{3}

= \dfrac{12}{1} \times \dfrac{3}{3} + \dfrac{2}{3}

= \dfrac{36}{3} + \dfrac{2}{3}

= \dfrac{38}{3}

4 0
3 years ago
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