5 + 5 + 10 = 20
x + y + z = 160
5 × 80 : 5 × 80 : 10 × 80
400 : 400 : 800
9x10^7
10x10=100x10=1,000
1,000x10=10,000
10,000x10=100,000
100,000x10=1,000,000
1,000,000x10=10,000,000
10,000,000x9=90,000,000
3x10^3
10x10=100x10=1,000
1,000x3=3,000
90,000,000/3,000=30,000
So 9x10^7 is 30,000x larger than 3x10^3
hope it helps!
Answer:
A normal model is a good fit for the sampling distribution.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
The information provided is:
<em>N</em> = 675
<em>X</em>₁ = bodies with low vitamin-D levels had weak bones
<em>n</em>₁ = 82
<em>p</em>₁ = 0.085
<em>X</em>₂ = bodies with regular vitamin-D levels had weak bones
<em>n</em>₂ = 593
<em>p</em>₂ = 0.01
Both the sample sizes are large enough, i.e. <em>n</em>₁ = 82 > 30 and <em>n</em>₂ = 593 > 30.
So, the central limit theorem can be applied to approximate the sampling distribution of sample proportions by the Normal distribution.
Thus, a normal model is a good fit for the sampling distribution.