Answer:
a = √93
a ≈ 9.64
Step-by-step explanation:
We can use the Pythagorean theorem for this: a² + b² = c²
c is given as the hypotenuse, which is the pole with a length of 17 ft
c² is 17²
b is a leg with a height of 14 ft
b² = 14²
We need to find the base leg, a, distance from the wall to the base of the pole.
Solve:
a² + 14² = 17²
a² + 196 = 289
a² = 93
a = √93
-Chetan K
Answer:
1.we know the perimeter of the triangle=x-3+x+6+x=3x+3
so,answer is (b)3x+3
2.area of the triangle=1/2*b*h
=1/2*x+2*2x+6=x+2*2x+6/2=2x^2+6x+4x+12/2=2x^2+10x+12/2=2(x^2+5x+6)/2=x^2+5x+6
so,answer is(b)x^2+5x+6
Answer:
See Below (Isolate the variables)
Step-by-step explanation:
13) d = 4AM solve for M
Divide both sides by 4A


14)
= f+h solve for A
Multiply both sides by 6
A = 6( f+h)
15) h - m = qb solve for H
Add m to both sides
h - m = qb
+ m +m
h = qb + m
If you’re asking for the answer, it’s 5
The answer is -19 1/2 feet