Question

A rock drops from a height of 60m. how long does it take for it to hit the ground?

Answer 1

To solve for the time an object takes to hit the ground, the equation

y = y₀ + v₀t + ½gt², or just 0 = y₀ +½gt² since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, t = (−2y₀/g)^½.

(-2*60/-9.8)^½ = 3.50 seconds.