Answer:
5x/7 - 3/7
Step-by-step explanation:
Formula for growth:
y = initial • (percent growth + 1)^time/frequency of growth
So, since initial population is 382
Percent growth is 0.007
The time is 30 years
And it goes it by .07% every 1 year,
y = 382 • (1.007)^30/1
y= 470.9203732 people
Since we can’t have 0.9 of a person, the population after 30 years will be 470 people.
I assume you're referring to a function,

where <em>a</em> is some unknown constant. By definition of the derivative,

Then

Answer:
c
Step-by-step explanation:
and bro i am i have a brother that always on my account makes me that im cheating that im not and he always blames me so thats why my bro has too many gfs and always blames me
Answer:
D = 11
Step-by-step explanation:
A = 4
B = 9
C = 11
D = 4 + (2 * 9) - 11
D = 4 + 18 - 11
D = 22 - 11
D = 11
brainliest plz