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vichka [17]
3 years ago
8

If y = (x - 3)^2 what is the value of y when x = 4?

Mathematics
2 answers:
tiny-mole [99]3 years ago
6 0
F. 1 Isherwood is the solution for this

ladessa [460]3 years ago
5 0

I'd say F--1.

Because, when you substitute 4 for x

y=(4-3)^2

y=(1^2)

y=1

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Penny's garden has alength of 16ft. and the width is 5 ft. with a rectangular fountain in the middle that measures 5 ft by 9 ft.
lilavasa [31]

First we need the whole garden:

16 x 5 = 80

Now we need to fountain:

5 x 9 = 45

Now to find our answer:

80 - 45 = 35

So our answer is B. 35ft²

4 0
3 years ago
(100 points)
LekaFEV [45]

Answer:

30/10 and 5/11

Step-by-step explanation:

8 0
3 years ago
Andrew goes to a store an buys an item that costs xx dollars. He has a coupon for 35% off, and then a 8% tax is added to the dis
ANTONII [103]

Answer:

xx(0.65) + xx(0.08)

Step-by-step explanation:

First step is to find the discounted price. Finding 35% less than the original xx is the same as finding 65% of it, so we multiply by 0.65. Once this is completed we need to find 8% more than that. So we add 8% of xx, which is the same as multiplying by 0.08. Hope this helps :)

7 0
2 years ago
To what expression must 5a square-4a+3 be added to make the sum zero??​
pychu [463]

Answer:

Step-by-step explanation:

Additive inverse of (5a² - 4a + 3) should be added to make them zero

(5a² - 4a + 3) + (-5a² + 4a - 3)=   <u>5a² - 5a² </u>  <u>- 4a + 4a</u>    <u>+ 3  - 3</u>

                                              = 0

4 0
2 years ago
How do you do this question?
Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0
2 years ago
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