Get into ax²+bx+c=0 form
subsitute u=x⁴
x⁸-3x⁴+2=0
(x⁴)²-3(x⁴)+2=0
u²-3u+2=0
factor
(u-2)(u-1)=0
set to zero
u-2=0
u=2
u-1=0
u=1
wait, u=x⁴
2=x⁴
![\sqrt[4]{2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%3Dx)
1=x⁴
+/-1=x
the subsitution is u=x⁴
and the possible values for x are -1,
![\sqrt[4]{2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%3Dx)
, and 1
We are given a trapezoid TRHY.
Height of the trapezoid = 13 units.
b1 = 21 units and
Area = 215 units squares.
We need to find the length of b2.
We know formula for area of a trapezoid.

Plugging values in formula.
215 =
(21+b2)× 13.
215 = 6.5(21+b2)
Dividing both sides by 6.5, we get

33.08 = 21+b2.
Subtracting 21 from both sides, we get
33.08-21 = 21-21+b2
b2 = 12.08.
<h3>Therefore, length of b2 is 12.08 units.</h3>
pretty much about the same as before.
a = weight of a large box
b = weight of a small box.
we know their combined weight is 65 lbs, thus a + b = 65.
we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

Step-by-step explanation:
<h2>=5/12</h2>
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