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Nata [24]
2 years ago
9

SOMEONE HELP ASAP PLEASE!

Mathematics
1 answer:
Tanzania [10]2 years ago
5 0
I hope this helps you

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mason made 5 quarts of salsa which of the following can be used to find the number of cups of salsa mason made
RUDIKE [14]

Answer:

I think its 20 cups, it doesn’t have a link for ‘the following’

probably not right I’m dum

8 0
3 years ago
Evaluate this exponential expression (27/8)^ 4/3<br><br> A: 9/2<br> B: 4/3<br> C: 81/16
valkas [14]

\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( \cfrac{27}{8} \right)^{\frac{4}{3}}\implies \left( \cfrac{3^3}{2^3} \right)^{\frac{4}{3}}\implies \left( \cfrac{3^{3\cdot \frac{4}{3}}}{2^{3\cdot \frac{4}{3}}} \right)\implies \cfrac{3^4}{2^4}\implies \cfrac{81}{16}

7 0
3 years ago
Will give me a 20% discount if I spend over $50 my bill is $75.What is my final bill after the savings
Andrews [41]
Hey there,
$75 is above $50
Final Bill = $75 - (20% x $75)
              = $75 - $15
              = $ 60

Hope this helps :))

<em>~Top♥</em>
7 0
3 years ago
Read 2 more answers
A baseball player hit 65 home runs in a season. Of the 65 home​ runs, 19 went to right​ field, 23 went to right-center​ field, 9
olchik [2.2K]

Answer:

a) 29.23% probability that a randomly selected home run was hit to right field

b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.

(a) What is the probability that a randomly selected home run was hit to right field?

Desired outcomes:

19 home runs hit to right field

Total outcomes:

65 home runs

19/65 = 0.2923

29.23% probability that a randomly selected home run was hit to right field

(b) Was it unusual for this player to hit a home run to right field?

29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

8 0
3 years ago
13. Solve for m. Assume that none of the denominatons are equal to 0<br>Plz help me​
givi [52]

Answer:

m = (ps - b - uxs/t) / ux/t - p

Step-by-step explanation:

ux/t +b/m+s =p

multiplying throughout by (m+s) we get:

ux/t(m+s) + b = p(m+s)

open the brackets:

uxm/t + uxs/t + b = pm + ps

bring on one side of the equal sign all terms containg m, to make it the subject:

m(ux/t - p) = ps - b - uxs/t

m= (ps - b - uxs/t) / ux/t - p

3 0
3 years ago
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