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anygoal [31]
3 years ago
6

Sorry I have trouble with math

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0

Answer:

okkk budyyyyyyyysjsj

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Y+7=19y -3 <br><br> ayuda .prometo dar mucho amor
Vladimir79 [104]

Answer:

y = 0.55 or 5 / 9

Step-by-step explanation:

here's the solution :-

=》y + 7 = 19y - 3

=》7 + 3 = 19y - y

=》18y = 10

=》y = 10 ÷ 18

=》y = 5 ÷ 9

=》y = 0.55

6 0
2 years ago
What is the decimal expansion of the fraction 7/9
lys-0071 [83]
0.7777777778
don't you have calculators or internet, you could easily find your question on internet 
6 0
3 years ago
Read 2 more answers
Find the slope of the line graphed below
igomit [66]

We are given two points: (-1, -1) and (1, -4). Slope is calculated as the change in y over the change in x, or rise over run.

The change in y is the difference of the two y coordinates (it doesn't matter the order): -1 - (-4) = 3

The change in x is the difference of the two x coordinates (this order depends on the order that you subtracted the y coordinates; they must be the same order): -1 - 1 = -2.

So, the slope is 3/-2

4 0
3 years ago
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What is the solution set for the inequality 6x-7&gt;5
zhenek [66]
Rearrange equation to get
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3 0
3 years ago
Find the angel x in d diagram above with a well structured solution.<br><br>Thanks​
Tom [10]

Step-by-step answer:

Please refer to attached image.

1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning

  that

  angles QPS and QRS are supplementary =>

  QPS+QRS=180   =>

  QRS = 180 - 74 = 106

2. Triangle RSQ is isosceles with RS=RQ =>

   angles RSQ and RQS are congruent.

3. Angle RSQ = (180 - 106) /2 = 74 / 2  = 37

4. QP is a diameter => angle QSP is a right-angle.

5. From (3) and (4) above,

  angle RSP = 37+90 = 127

6. Since PQRS is cyclic, angles RQP  and RSP are supplementary =>

   RQP+RSP = 180   =>

   x + 127 = 180   =>

   x = 180 - 127 = 53 degrees.

5 0
3 years ago
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