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3 years ago

URGENT!! PLEASE HELP!!!

Mathematics

1 answer:

olga55 [171]3 years ago

9 0

Answer:

The correct option is B.

Step-by-step explanation:

The formula for amount after compound interest is

$A=P(1+\frac{r}{n})^{nt}$

Where P is principal, r is rate of interest, n is number of times interest compounded in a period, t is number of years.

It is given that Felix took out an unsubsidized student loan of $40,000 at a 3.6% APR, compounded monthly. The amount after 33 month is

$A=40000(1+\frac{0.036}{12})^{33}=44156.1074$

The amount after 33 month is $44156.1074. So, the new principle amount is $44156.1074.

The monthly payment of $44156.1074 for 20 years is

$m=\frac{P.V.(\fracr)}{1-(1+r)^{-n}}$

Where, P.V. is present value, r is rate of interest and n is number of times interest compounded.

$m=\frac{44156.1074(\frac{0.036}{12})}{1-(1+\frac{0.036}{12})^{-20\times 12}}$

$m=258.362447711$

$m\approx 258.36$

Therefore the correct option is B.

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8^0 is greater than 8^1 true or false

liq [111]

Answer:

False 8^0 is not greater than 8^1

Step-by-step explanation:

8^0 = 1

8^1= 8

8>1

3 0

3 years ago

Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

3 years ago

How to find the volume of L blocks?

choli [55]

<span>Volume = L * W * H cubic units

Surface Area = 2 * (LW + LH + WH) square units</span>

5 0

4 years ago

Which expression is equivalent to 63 + 27?

azamat

The answer would be B.

5 0

3 years ago

Can you please explain this?

Leni [432]

Answer:

The question is giving you pairs of points in space which can be used to define lines. It is then asking you to determine if the lines defined by those points are parallel, perpendicular, or neither.

Step-by-step explanation:

Two key things you need to know to solve this is that the lines will be parallel if their slopes are the same, and perpendicular if one slope is the negative reciprocal of the other (i.e. $s_{1} = -s_{2}^{-1}$ )

Let's start with question 11. You are given two pairs of points, each of which describes a distinct line:

(3,5)-(1,1) and (0, 2)-(5, 12)

To find the slope of each pair, take the vertex with the lesser x co-ordinate, and subtract it from the vertex with the greater x co-ordinate. That will give us a valid Δx and Δy to get the slope.

In the first pair, 3 > 1, so we'll subtract the second point from the first:

$s = \Delta y / \Delta x\\s = \frac{5 - 1}{3 - 1}\\s = 4/2\\s = 2$

So the first pair of vectors describe a line with a slope of 2. Let's look at the other pair:

$s = \Delta y / \Delta x\\s = (12 - 2) / (5 - 0)\\s = 10 / 5\\s = 2$

That also gives us a slope of 2, meaning that the two lines are parallel.

This same process will need to be done for the other three questions. We can't answer questions 12 or 14 here, as the last point is cut off on the edge of the image. For question 3 though, one line has a slope of 7/3, and the other 3/7. That puts them in the "neither" category, as one is not the negative reciprocal of the other, but instead the positive reciprocal.

6 0

3 years ago