Question

Find four consecutive integers whose sum is -26 With steps Please !

Answer 1

You can do it without trial and error by setting the first integer to x. Since the other integers are consecutive, the next number would be x +1, next would be x + 2, and then finally x +3

Add them together and set them to equal to -26, then solve for x.

x + (x+1) + (x+2) + (x+3)= -26
4x + 6 = -26
4x = -32
x = -8

the first number is -8, so x+1 is -7, x+2 is -6 and x + 3 is -5.

So your consecutive integers are -8,-7,-6, and -5, which when added together gives you -26.

Answer 2

Well, when i get a question like this I use trial and error.
for example lets start with -5, -6, -7, and -8= -26

which in this case does equal the target number but lets say it didn't.  If you got a number that was to high you start with a lower number and if you got a number that was to low you start with a higher number.

hope this helps!