Answer:
1, 0.4
2, 0.004
3, 0.04
Step-by-step explanation:
hope this helps. :)
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
x = 4
Step-by-step explanation:
The absolute value of 5x is still 5x.
5x - 2 = 18
Add 2 to both sides
5x = 20
Divide both sides by 5
x = 4
Formula of the sum of the 1st nth term in a Geometric Progression:
Sum = a₁(1-rⁿ)/(1-r), where a₁ = 1st term, r = common ratio and n= rank nth of term (r≠1)
Sum = (-11)[1-(-5⁸)] /[(1-(-5)]
Sum = (-11)(1- 390625)/(6)
SUM = 716,144
(x + y = 125)3
5x - 3y = 41
3x - 3y = 375
8x = 416, x = 52
52 + y = 125, y = 73
Solution: the numbers are 52 and 73
