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Contact [7]
4 years ago
14

The ordered array below represents the number of cargo manifests approved by customs inspectors of the Port of New York in a sam

ple of 35 days: 16, 17, 18, 18, 19, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 25, 25, 26, 26, 26, 27, 28, 28, 29, 29, 31, 31, 32, 32 Note: For this sample, the sum of the values is 838, and the sum of the squared differences between each value and the mean is 619.89. Referring to Scenario 3-4, the third quartile of the customs data is
Mathematics
1 answer:
Lapatulllka [165]4 years ago
7 0

Answer:

the third quartile of the customs data is 27

Step-by-step explanation:

For the third quartile, we should first find upper half of the data and then the median of the upper half.  

lower half: 16, 17, 18, 18, 19, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23,

median: 23

upper half: 24, 24, 24, 25, 25, 26, 26, 26, 27, 28, 28, 29, 29, 31, 31, 32, 32

Middle value (median) of the upper half is: 27 since 8 of the values are lower than 27 and 8 of the values are higher than 27.

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Please solve this<br> 21,20,40,78,...,77<br> A. 38<br> B. 76<br> C. 74<br> D. 78<br> E. 70
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