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3 years ago

The additive inverse of 10 is -17. If 10 + (-17) = 0, then the numbers are additive inverses. True or False?

Mathematics

1 answer:

Vesnalui [34]3 years ago

3 0

Answer:

False

Do not worry I am not giving you any false answers

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A mobile phone company uses the formula C = 10t + 20m to calculate the total cost of a bill. C is the total cost of the bill in

Irina-Kira [14]

Total Cost C = 10*150 + 20*50

= 2500 pence

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3 years ago

if you take my age and divide it by any off number greater than 1 and less than 9 you will get a remainder of 1

postnew [5]

Answer:

no???

Step-by-step explanation:

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3 years ago

Use substitution to solve the system of equations.

dusya [7]

Answer:

Step-by-step explanation:

1/2(2/3y) - 1/3y = 5

1/3y - 1/3y = 5

0 ≠ 5

No Solutions

These are linear equations and, when graphed, are parallel

7 0

3 years ago

Select "Growth" or "Decay" to classify each function.

allochka39001 [22]

1. The growth rate equation has a general form of:

y = A (r)^t

The function is growth when r≥1, and it is a decay when r<1. Therefore:

y=200(0.5)^2t --> Decay

y=1/2(2.5)^t/6 --> Growth

y=(0.65)^t/4 --> Decay

2. We rewrite the given equation (1/3)^d−5 = 81

Take the log of both sides:

(d – 5) log(1/3) = log 81

d – 5 = log 81 / log(1/3)

d – 5 = - 4

Multiply both sides by negative 1:

- d + 5 = 4

So the answer is D

5 0

3 years ago

An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle

omeli [17]

Answer:

$\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

$\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}$

The middle point of the base is placed at point

$\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i$

The length of the height is the distance between the points 5+9i and 7+3i

$\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}$

So, the area of the triangle is

$A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

4 0

3 years ago