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Sedaia [141]
3 years ago
7

Marcel said he can find 52 times 10 by adding a 0 to the end of 52 to get 520

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

No he can not because if you add 0 to 52 you get 520 and the answer has to be 520

Step-by-step explanation:

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4 years ago
Rachel is a lunchroom supervisor at West School. The children eat lunch at 15 long tables. When all tables are used, 240 childre
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3 years ago
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Using the image, determine the length of each arc.<br> m RC=<br> m CBR =
Montano1993 [528]

<u>Given</u>:

Given that the measure of ∠CDR = 85°

We need to determine the measure of \widehat{RC} and \widehat{CBR}

<u>Measure of arc RC:</u>

Since, we know that if a central angle is formed by two radii of the circle then the central angle is equal to the intercepted arc.

Thus, we have;

m\angle CDR = m \widehat{RC}

Substituting the values, we get;

85^{\circ} = m \widehat{RC}

Thus, the measure of \widehat{RC} is 85°

<u>Measure of arc CBR:</u>

We know that 360° forms a full circle and to determine the measure of arc CBR, let us subtract the values 360 and 85.

Thus, we have;

m\widehat{CBR}=360^{\circ}-m \widehat{RC}

Substituting the values, we have;

m\widehat{CBR}=360^{\circ}-85^{\circ}

m\widehat{CBR}=275^{\circ}

Thus, the measure of \widehat{CBR} is 275°

6 0
4 years ago
Find the radius of convergence, then determine the interval of convergence
galben [10]

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.  

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = β

  • If β < 1, then the series converges
  • If β > 1, then the series diverges
  • If β = 1, then the series inconclusive

Here a_{k} = \frac{(x+2)^{k}}{\sqrt{k} }  and  a_{k+1} = \frac{(x+2)^{k+1}}{\sqrt{k+1} }

   

Now limit is taken,

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|

= \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|

= \lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|

= |{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}

= |{x+2 }| < 1

- 1 < {x+2 } < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

 

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

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Fiesta28 [93]

Answer: -1/3

Step-by-step explanation:

The formula is y2 - y1/ x2 - x1 . So the answer would be -1/3 bc 3 - 2 = 1 and -11 - (-8) = -3.

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