Right side:
(1/27)^(2x+10)
=(3^-3)^(2x+10)
= 3^(-6x - 30)
Re-write both sides:
3^(4x-5) = 3^(-6x - 30)
from here, you can solve x
4x - 5 = -6x - 30
4x + 6x = -30 + 5
10x = -25
x = -2.5
How many brothers does everyone here have?
Answer:

Step-by-step explanation:
The equation
is a <em>linear equation</em>. By definition, the independent term on this equation (that is, the number that is not being multiplied by
) is the <em>y-intercept</em>, which is a fancy way of saying "the point where the line crosses the y-axis".
By looking at the equation, we know that our y-intercept is <em>c. </em>By looking at the graph, we can see that the y-intercept is -3. Therefore,
and we get the complete version of our linear equation:

Now, looking at the graph we can see that the point
lies on the line of the equation, which means that the point is a solution to our equation. All we have to do is replace
and
by the values of the given point (which are
and
, respectively), and then solve for
:

And we are done!
Answer:
x ∈ {-5, -1}
Step-by-step explanation:
Here's the solution using the quadratic formula:

The real zeros are -5 and -1.
_____
There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.
Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.
Answer:
t ≤ 15
Step-by-step explanation:
One third of 15 is equal to five (1/3 × 15 = 5)
One third of t is lesser than or equal to five (1/3 × 5 ≤ 5)
<em>So, t cannot be more than 15.</em><em> </em><em>It</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>1</em><em>5</em><em>,</em><em> </em><em>though</em><em>.</em>
∴t ≤ 15