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dsp73
2 years ago
9

What is the GCF of: -12x^2 + 6x - 36

Mathematics
1 answer:
ankoles [38]2 years ago
3 0

Answer:

5,000,000?

Step-by-step explanation:

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Write an equation in slope-intercept form of<br> the line that passes through (-6,4) and<br> (-1,2).
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Answer:

Step-by-step explanation:

(-6 , 4)  & (-1 , 2)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}

m = -2/5   & (-6 , 4)

y -y1 = m(x -x1)

y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}

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3 years ago
Please help this is dew in 20 minutes
daser333 [38]

Answer:

It would be A.

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2 years ago
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Why and when do we cross multiply in algebra?
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What are the values of a, b and c in the quadratic equation -2x^2+4x-3=0?
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Answer:

a=-2\\b=4\\c=-3

Step-by-step explanation:

In a quadratic equation in the Standard form

ax^2+bx+c=0

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: a\neq0).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

-2x^2+4x-3=0

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a=-2\\b=4\\c=-3

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