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3 years ago

Multiply. (3x+ 5)(3х - 5)

Mathematics

2 answers:

brilliants [131]3 years ago

8 0

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Hi my lil bunny!

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$9x^2 - 25$

Explanation:

$( a + b) ( a - b ) = a^2 - b^2$

Substitute with 3x and b with 5:

$(3x + 5) (3x - 5) = (3x)^2 - 5^2\\$

$= 9x^2 - 25$

∴ $( 3x + 5) ( 3x - 5) = 9x^2 - 25$

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

densk [106]3 years ago

4 0

Answer:

9x^2-25

Step-by-step explanation:

You can solve this problem by using FOIL:

- FOIL (First, Outer, Inner, Last)

First: 3x*3x= 9x^2

Outer: 3x*-5= -15x

Inner: 3x*5 = 15x

Last: 5*-5= -25

Now add what we got together:

9x^2 -15x +15x -25

Answer: 9x^2 - 25

Note: Whenever when we see conjugates(coefficients of variables are same but real numbers are opposites) like these we can ignore the outer and inner of the foil process as they cancel out.

Hope this helps!

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Answer:

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Step-by-step explanation:

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3 years ago

suppose y varies directly with x and y=5 when x=20. Write a direct variation equation then find the value of x when y=3/2

jek_recluse [69]

X=k*Y
K*Y=X
K=X/Y
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3 years ago

The manager of a music store has kept records of

Marysya12 [62]

Answer:

(a) $P(x\le 3) = 0.75$

(b) $P(x\le 3) = 0.75$

(b) is the same as (a)

(d) $P(x = 1\ or\ 2) = 0.55$

(e) $P(x > 2) = 0.45$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

Solving (b): Probability of at most 3 CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

(b) is the same as (a)

Solving (c): Probability of 5 or more CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x \ge 5) = P(5) + P(6\ or\ more)$

This gives:

$P(x\ge 5) = 0.05 + 0.05$

$P(x \ge 5) = 0.10$

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}$

This probability is calculated as:

$P(x = 1\ or\ 2) = P(1) + P(2)$

This gives:

$P(x = 1\ or\ 2) = 0.30 + 0.25$

$P(x = 1\ or\ 2) = 0.55$

Solving (e): Probability of more than 2 CDs

Here, we consider:

$\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)$

This gives:

$P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05$

$P(x > 2) = 0.45$

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3 years ago

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irga5000 [103]

Answer:

Scalene Triangle

Step-by-step explanation:

If you mark the points on the graph, all three sides have different lengths and angles, therefor it is a scalene triangle.

It cannot be a right triangke bc there is no right angle, and no obtuse either so that crosses out obtuse as an option as well. In order to be an isoceles triangle it must have two sides of equal length, but it does not.

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3 years ago

If b is the midpoint of ac, ac=cd, ab=3x+4, ac=11x-17, and ce=49, find de

IrinaK [193]

First, we draw our line.

|------------------------------------------------------------------------------------|

a e

Next, break up this line into segments using the information.

|----------------------|----------------------|--------------------|------------------|

a b c d e

The entire line is 29.

ab + bc + cd + de = ae

ab + bc + cd + de = 29

You also know that

bd = bc + cd

Due to midpoint theorem,

ab = bc

cd = de

Then,

2ab + 2cd = 29

The equations we will use are

bd = bc + cd eq1

2bc + 2cd = 29 eq2

Dividing both sides of the equation in eq2 yields

bc + cd = 14.5

bd = bc + cd

bd = 14.5

5 0

3 years ago

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