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Alekssandra [29.7K]

3 years ago

6

A solid lies between planes perpendicular to the x-axis at x=0 and x=3. The cross-sections perpendicular to the axis on the inte

rval 0≤x≤3 are squares whose diagonals run from the parabola y=−x‾‾√ to the parabola y=x‾‾√.Find the volume of the solid.

1 answer:

Hatshy [7]3 years ago

6 0

Answer:

V = 9

Step-by-step explanation:

You can see it in the picture.

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in a bag of keys there are 15 silver keys six black keys 11 copper keys and two painted keys of various colors. one key is drawn

Setler79 [48]

Answer:

The best thing to do here is to put each of these into fractions, with the total (31) as the denominator.

14/31= silver

6/31= black

8/31= copper

3/31= various colours.

As you're looking for the keys that are silver or copper, you've got to add the two denominators together, which gives you 14+8= 22.

This cannot be simplified further, therefore, the probability of choosing either a silver or copper key is 22/31.

Hope this answer helps you :)

Have a great day

Mark brainliest

7 0

3 years ago

What will happen to the ratios as you increase the number of sides of the regular polygon?

earnstyle [38]

Answer: increase

Step-by-step explanation:

Number of sides of the polygon, The number of sides of a regular polygon and the measure of the exterior angle are inversely proportional. <em><u>As one quantity increases, the other decreases and vice versa.</u></em>

4 0

3 years ago

PLEASE HELP !!!!!!!!!!

umka21 [38]

Answer:

3 quarters

7 dimes and a nickel

7 dimes and 5 pennies

15 nickles

75 pennies

2 quarters 2 dimes and a nickel

etc.

Step-by-step explanation:

4 0

3 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

4 years ago

The students at Woodward elementary voted for school mascot. The falcon won with 5/8 of the votes. If 536 students voted for a m

drek231 [11]

The answer equals 335

3 0

4 years ago