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Georgia [21]
3 years ago
6

A town has a population of 4000 and grows at 3.5% every year. To the nearest year, how long will it be until the population will

reach 7500?
Mathematics
1 answer:
liraira [26]3 years ago
4 0

Answer:

The correct answer is 25 years.

Step-by-step explanation: If the population increases by 3.5 %, and the population to start off with is 4,000, this means the population will increase by 140 people every year. (4,000 x 0.035= 140) 140 x 25= 3,500 thus 4,000+ 3500= 7500... 25 years

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Decimal of 0.516÷4 With process​
steposvetlana [31]
Answer: 0.129
explanation:
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3 years ago
What is the solution to the equation?<br> 3 (4x– 1) + x = 5x – 4 (1 – 2x) + 1
Scorpion4ik [409]

Answer:

x=1

Step-by-step explanation:

12x -3 + x =5x - 4 +8x +1

13x-3=13x - 3

+3     +3

____________-

13x=13x

÷13x   ÷13x

_________

x=1

Hope this helps :D  (idk if its right srry if not)

8 0
3 years ago
What percentage of 100 is 35
nika2105 [10]

Answer:

35%

You divide 35 to 100

35÷100=0.35

and its equal to

35%

6 0
3 years ago
In 5 rounds of a game, Jill scored -3,8,9,-7, and 13. What integer represents her average score for the 5 rounds?
IgorC [24]
The answer is 9 because 5*(-3)+8+9-(-7)=9
5 0
4 years ago
Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

t=0\implies f(10,0)=155

t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299

t=\pi\implies f(-10,0)=235

t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0
3 years ago
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