Learn this...it helps
HOY = horizontal line, 0 slope, represented by x = a number
VUX = vertical line, undefined slope, represented by x = a number
undefined slope -- so its a vertical line
(5,-8)...remember, vertical lines are represented by x = a number....so we can say x = (now, what is the number for x in ur set of points ? it is 5...so ur equation is x = 5. it does not matter what value y is, x is ALWAYS gonna be 5
Let
![x=\arctan y](https://tex.z-dn.net/?f=x%3D%5Carctan%20y)
. Then
![\tan x=y](https://tex.z-dn.net/?f=%5Ctan%20x%3Dy)
, and so as
![x\to\dfrac\pi2^-](https://tex.z-dn.net/?f=x%5Cto%5Cdfrac%5Cpi2%5E-)
, you have
![y\to+\infty](https://tex.z-dn.net/?f=y%5Cto%2B%5Cinfty)
. The limit is then equivalent to
Answer:
B) 15.85%
Step-by-step explanation:
normalcdf(minimum,maximum,μ,σ)
normalcdf(39,189,264,75)
≈0.1573
≈15.73%
Therefore, the closest answer is B
Answer:
2. 1 / a^2
3, 1
4. - 1
Step-by-step explanation:
Formulas : -
x^y / x^z = x^( y - z )
x^-y = 1 / x^y
x^y / x^y = 1
2.
a^2 / a^4
= a^( 2 - 4 )
= a^-2
= 1 / a^2
3.
m^6 / m^6 = 1
4.
- 8^4 / 8^4
= - 1 x 8^4 / 7^4
= - 1
Answer:
Check bolded below
Step-by-step explanation:
1)radius = 10 in (given), diameter = 2*radius = 2(10 in) = 20 in
formula for circumference => 2πr => 2π(10)
circumference = 20π in
2)diameter = 12 ft (given), radius = 1/2*diameter = 1/2(12 ft) = 6 ft
formula for circumference => 2πr => 2π(6)
circumference = 12π ft
3)radius = 3 m (given), diameter = 2*radius = 2(3 m) = 6 m
formula for circumference => 2πr => 2π(3)
circumference = 6π m
4)diameter = 18 cm (given), radius = 1/2*diameter = 1/2(18 cm) = 9 cm
formula for circumference => 2πr => 2π(9)
circumference = 18π cm