25 percent
25 plus 20 is 45
60 minus 45 is 15
15 divided by 60 is .25
.25 times 100 is 25
25%
Answer: (ii) We reject H0---this sample provides significant evidence that the program is effective.
Step-by-step explanation:
The null hypothesis is
The program is not effective for weight loss.
The alternative hypothesis is
The program is effective for weight loss.
If the P-value for the test turns out to be 0.012, and the level of significance is 0.05, then
Alpha, 0.05 > p value, 0.012
Therefore, there is enough evidence to reject the null hypothesis. We then accept the alternative hypothesis.
The correct option is
(ii) We reject H0---this sample provides significant evidence that the program is effective.
Answer:
Equation: y = ⅐x
Rate of change: ⅐
Distance = 10 miles
Step-by-step explanation:
Given
The information in the above table
Solving (a): The equation
To get the equation, we need to first calculate the slope (m)
Take any two corresponding values of x and y
(x1,y1) = (7,1)
(x2,y2) = (21,3)
m = (y2 - y1)/(x2 - x1)
m = (3 - 1)/(21 - 7)
m = 2/14
m = ⅐
The equation is calculated using
y - y1 = m(x - x1)
Substitute values for m, x1 and y1
y - 1 = ⅐(x - 7)
y - 1 = ⅐x - 1
Add 1 to both sides
y = ⅐x
Solving (b) Rate of change:
The calculated slope in (a) above represents the rate of change.
So:
Rate of change = Slope = ⅐
Solving (c): Distance when time is 70 minutes
This implies that x = 70
Substitute 70 for x in y = ⅐x
y = ⅐ * 70
y = 10 miles
The Correct Answer Is B.36 square centimeters
Hope this helps
Answer:
The dimensions of the box are:
Length = 11.53cm
Breadth = 11.53cm
Height = 11.53cm
Step-by-step explanation:
The volume of the box can be calculated with this formula:
The volume of the box = area of square base X height of the box.
We are given that the length of one side of the square base is = x cm, and its height is h cm.
Area of square base = 
The surface area of the box will be minimized if the height of the box, is the same as its length. hence, we can take the height of the box to be x cm also.
In this case, the volume of the box will be 
from this, 
There fore, the box has its length, height, and width all having the same values.
The dimensions of the box are:
Length = 11.53cm
Breadth = 11.53cm
Height = 11.53cm