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zvonat [6]
3 years ago
11

Write a simplified polynomial expression in standard form to represent the area of the rectangle below. (2 points) A picture of

a rectangle is shown with one side labeled as 5 x plus 2 and another side labeled as x minus 4.
Mathematics
2 answers:
Anna71 [15]3 years ago
5 0

Answer:

C

Step-by-step explanation:

 

5x2 − 18x − 8

Jet001 [13]3 years ago
4 0

Answer:

Area= 5x^2-18x -8

Step-by-step explanation:

If the rectangle show one side of length 5 x +2, and another side of length x - 4, then the area of this rectangle (given by the product of the sides' length) is:

Area = (5x+2)\,(x-4)\\Area = 5x^2-20x+2x-8\\Area= 5x^2-18x -8

which is already written in standard form.

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Rudik [331]

Answer:

200

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8 0
3 years ago
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i know this is probably simple but ive forgotten how to do it and i cant find it in my notes help appreciated!
Soloha48 [4]

Answer:

? = 13.6

Step-by-step explanation:

the angle between a tangent and the diameter = 90°

Then the triangle is right with legs 2 × 6 = 12 and 6.4

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the legs , that is

? ² = 12² + 6.4² = 144 + 40.96 = 184.96 ( take square root of both sides )

? = \sqrt{184.96} = 13.6

6 0
2 years ago
A jar of peanut butter weighs 7 ounces, and a jar of jelly weighs 4 ounces. If Karen buys 8 jars of peanut butter, how many jars
ad-work [718]
Karen will have to buy 14 jars to have an equal weight of peanut butter
7 0
3 years ago
Subtract 23.4 − 8.78 =_____
Alona [7]
<span>14.62 super simple, good luck with any other questions!</span>
5 0
4 years ago
Read 2 more answers
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
3 years ago
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