80 in word form
Eighty
Hope this helped!
Answer:
125
Step-by-step explanation:
5*5*5
Answer:
x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4
Step-by-step explanation:
Solve for x:
x - 1 - 2/x = 3 x + 2
Bring x - 1 - 2/x together using the common denominator x:
(x^2 - x - 2)/x = 3 x + 2
Multiply both sides by x:
x^2 - x - 2 = x (3 x + 2)
Expand out terms of the right hand side:
x^2 - x - 2 = 3 x^2 + 2 x
Subtract 3 x^2 + 2 x from both sides:
-2 x^2 - 3 x - 2 = 0
Divide both sides by -2:
x^2 + (3 x)/2 + 1 = 0
Subtract 1 from both sides:
x^2 + (3 x)/2 = -1
Add 9/16 to both sides:
x^2 + (3 x)/2 + 9/16 = -7/16
Write the left hand side as a square:
(x + 3/4)^2 = -7/16
Take the square root of both sides:
x + 3/4 = (i sqrt(7))/4 or x + 3/4 = -(i sqrt(7))/4
Subtract 3/4 from both sides:
x = (i sqrt(7))/4 - 3/4 or x + 3/4 = -(i sqrt(7))/4
Subtract 3/4 from both sides:
Answer: x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4
V=(l)(w)(h) = (1/2)(2)(7/2)=14/4 in 3 14 divided by 4 = 3 2/4 in 3 3 x 4+2= 14 so 14 in 3 is the answer for (A)
Answer:
1) x ≤ 2 or x ≥ 5
2) -6 < x < 2
Step-by-step explanation:
1) We have x^2 - 7x + 10, so let's factor this as if this were a regular equation:
x^2 - 7x + 10 = (x - 2)(x - 5)
So, we now have (x - 2)(x - 5) ≥ 0
Let's imagine this as a graph (see attachment). Notice that the only place that is above the number line is considered greater than 0, and that's when x ≤ 2 or x ≥ 5 (the shaded region).
2) Again, we have x^2 + 4x - 12, so factor this as if this were a regular equation:
x^2 + 4x - 12 = (x + 6)(x - 2)
So now we have (x + 6)(x - 2) < 0
Now imagine this as a graph again (see second attachment). Notice that the only place that is below 0 (< 0) is when -6 < x < 2 (the shaded region).
Hope this helps!
