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ZanzabumX [31]
3 years ago
3

A graph has outside Temperature (degrees Fahrenheit) on the x-axis, and sales of iced tea (dollars) on the y-axis. Points are at

(30, 69), (71, 78), (37, 30), (48, 103), (40, 60), (80, 120), (92, 145).
Which two points should the trend line go through to best represent the data given in this scatterplot?

(30, 69) and (71, 78)

(37, 30) and (48, 103)

(40, 60) and (71, 78)

(40, 60) and (80,120)

Mathematics
1 answer:
dusya [7]3 years ago
6 0

Answer:40,60 80,120

Step-by-step explanation:

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Mrrafil [7]

Answer:

i dont know

Step-by-step explanation:

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3 years ago
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All Parent functions have both x- intercepts and y-intercepts EXCEPT. I. Linear II. Absolute Value III.Quadratic IV. Cubic V.Squ
stealth61 [152]

Answer:

Reciprocal, Exponential and Logarithmic.

Step-by-step explanation:

x intercept is the value of x where y value is 0.

y intercept is the value of y where x value is 0.

Let us have a look at the possibility for <em>each parent function </em>as given.

I. Linear

y =x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

II. Absolute value

y =|x|

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

III. Quadratic

y =x^{2}

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

IV. Cubic

y =x^3

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

V. Square root

y =\sqrt x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

VI. Cube root

y =\sqrt[3]x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

VII. Reciprocal

y =\dfrac{1}x

When x = 0, y \rightarrow \infty

Therefore, both x and y intercept do not exist.

VIII. Exponential

y =b^x

where b is any base:

When x = 0, y =1 therefore y intercept exists.

When we put y = 0, which is not possible

Therefore, both x and y intercept do not exist.

IX. Logarithmic

y =logx

When x = 0, y \rightarrow not defined

Therefore, both x and y intercept do not exist.

6 0
3 years ago
A rectangle with an area of 25 square centimetres is rotated and reflected in the coordinate plane. What will be the area of the
ahrayia [7]
Step by step answer by answer choice by choice
5 0
3 years ago
Tomas learned that the product of the polynomials (a b)(a2 – ab b2) was a special pattern that would result in a sum of cubes, a
soldier1979 [14.2K]

The polynomial (a + b)(a² – ab + b²) is reconstructed as (2x + y)(4y² – 2xy + y²), then the correct option is C.

<h3>What is polynomial?</h3>

Polynomial is an algebraic expression that consists of variables and coefficients. Variables are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.

Tomas learned that the product of the polynomials (a + b)(a² – ab + b²) was a special pattern that would result in a sum of cubes, a³ + b³.

His teacher put four products on the board and asked the class to identify which product would result in a sum of cubes if a = 2x and b = y.

Then the polynomial equation will be

(2x + y)(4y² – 2xy + y²)

More about the polynomial link is given below.

brainly.com/question/17822016

8 0
2 years ago
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A bookstore classifies its books by reader group, type of book, and cost. What is the probability that a book selected at random
Murrr4er [49]

Answer:

Pr(Cb) & Pr(cost $15) = 15(Ncb)/(T1×T3)

Step-by-step explanation:

Classification of the book in to 3

First let's assign terms to each probability

Let:

T1= total number of type of Reader's group

T2 = total number of Type of book

T3 = total number of type of Cost

Probability of child's book and cost $15= Pr(Cb) & Pr(cost $15)

Then find probability of child's book and cost separately:

Pr of child's book = Pr(Cb)

Pr(Cb) = (number of child's book)/ total number of type of group

Ncb = number of child's book

Pr(Cb) = Ncb/T1

Pr (cost $15) = $15 book/total number of cost

Pr (cost $15) = 15/T3

probability of child's book and cost $15 = Pr(Cb) × Pr (cost $15)

= Ncb/T1 × 15/T3

Pr(Cb) & Pr(cost $15) = 15(Ncb)/(T1×T3)

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