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irina1246 [14]
3 years ago
15

Where does the oxygen that is used during cellular respiration in animals

Mathematics
1 answer:
Softa [21]3 years ago
6 0

Answer:

A. Air that is breathed in :)

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D/5 = 4 please explain I do not get this. Thank you
MAXImum [283]
<span>D/5 = 4
Multiply 5 on both sides
Final Answer: D = 20</span>
8 0
3 years ago
The price of a watch was increased by 7% to £1350. What was the price before the increase? Give your answer to the nearest penny
frutty [35]

Answer:

1261.68

Step-by-step explanation:

1350 = the increased watch price= 107% of the original

1350= 1.07x

1261.68224299

Check:

7% of 1261.68224299 is 88.317757

1261.68224299 + 88.317757 = 1349.9 = 1350

Round:

1261.68224299  

To the penny= to the hundreth= 1261.68

3 0
3 years ago
HELP PLS i’ll mark as brainliest if correct
Vlada [557]

Answer:

I believe the answer is the second one

Step-by-step explanation:

7 0
3 years ago
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PLSSSSS HELPPP solve for x, round to nearest tenth
inessss [21]

Answer:

17.6

Step-by-step explanation:

7 0
2 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
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