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love history [14]
3 years ago
7

One factor of the polynomial 6x3 − x2 + 8x + 5 is (2x + 1). What is the other factor of the polynomial? (Note: Use long division

.)
Mathematics
2 answers:
Verizon [17]3 years ago
6 0

Answer: (3x2 − 2x + 5)

Step-by-step explanation:

maria [59]3 years ago
4 0

Answer:

(3x^2 - 2x + 5)

Step-by-step explanation:

3x^2 - 2x + 5

2x + 1 \sqrt{6 {x}^{3}  -  {x}^{2}  + 8x + 5  }

- <u>(6x^3 + 3x^2)</u>

-4x^2 +8x +5

- <u>(-4x^2 - 2x)</u>

10x + 5

-(<u>10x + 5)</u>

00

(2x+1) (3x^2 - 2x + 5) = 6x^3 - x^2 + 8x + 5

Therefore the other factor of the polynomial is (3x^2 - 2x + 5)

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Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>
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<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

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