All categories

3 years ago

What is negative three-fourth times eight

Mathematics

2 answers:

marishachu [46]3 years ago

5 0

The answer would end up being -6.

wel3 years ago

3 0

I have to have at least 20 characters to submit the answer. The answer is -6

You might be interested in

Need help fast plz for my pre calc exam

bezimeni [28]

Answer:

h = 8.54 units

Step-by-step explanation:

The Law of Cosines

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

$c^2=a^2+b^2-2ab\cos x$

Since we know the values of all three side lengths, we solve the equation for x:

$\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}$

For the triangle ABC in the image, a=10, b=15, c=13, thus:

$\displaystyle \cos A=\frac{10^2+15^2-13^2}{2*10*15}$

$\displaystyle \cos A=\frac{156}{300}$

$\displaystyle \cos A=0.52$

Thus, A = 58.67°

For the right triangle of height h and hypotenuse 10, we use the sine ratio:

$\displaystyle \sin 58.67^\circ=\frac{h}{10}$

Solving for h:

$h = 10\sin 58.67^\circ$

h = 8.54 units

6 0

3 years ago

Four percent of Jennie's skin cells were burned when she escaped from a fire. If 3.7 x 10^10 of her skin cells were burned then,

baherus [9]

Answer:

355.2

Step-by-step explanation:

Given:

Four percent of Jennie's skin cells were burned

Total skin cells having Jennie = 3.7 x 10^10

= $3.7\times10\times10 = 370$

To find:

How man skin cells were not burned ?

Solution:

Total skin cells having Jennie = 370

Percent of Jennie's skin cells were burned = 4%

Skin cells burned from a fire = $370 \ of 4\%$

= $370\times\frac{4}{100} =\frac{1480}{100}$

= $14.8$

Remaining skin cells which not burned = 370 - 14.8 = 355.2

Therefore, 355.2 skin cells were not burned.

8 0

3 years ago

Each person in a ticket line gets either one or two tickets. You are the 51st person in line. Forty percent of the people in fro

Marrrta [24]

80 tickets have been given out

50*.4=20
50*.6=30
30*2=60
60+20=80

5 0

3 years ago

11. The domain of f(x) is [4, 5, 6]. If f(x) = 3x + 2, what is the range?

grigory [225]

Answer:

The range of the function is:

Range R = {14, 17, 20}

Step-by-step explanation:

Given the function

$f(x) = 3x + 2$

We also know that range is the set of values of the dependent variable for which a function is defined.

In other words,

Range refers to all the possible sets of output values on the y-axis.

We are given that the domain of the function is:

Domain D = {4, 5, 6}

Now,

substituting x = 4 in the function

f(4) = 3(4) + 2

f(4) = 12 + 2

f(4) = 14

substituting x = 5 in the function

f(5) = 3(5) + 2

f(5) = 15 + 2

f(5) = 17

substituting x = 6 in the function

f(6) = 3(6) + 2

f(6) = 18 + 2

f(6) = 20

Thus, we conclude that:

at x = 4, y = 14

at x = 5, y = 17

at x = 6, y = 20

Thus, the range of the function is:

Range R = {14, 17, 20}

3 0

3 years ago

Find the equation of the line that passes through point A (1,7) and B (-3, -1)

amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( $x_{1}, y_{1}$ ) & ( $x_{2}, y_{2}$ )-

y - $y_{1}$ = $\frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }$ ( x - $x_{1}$ )

i.e. y - 7= $\frac{- 1 - 7}{ -3-1}$ ( x- 1)

y - 7 = $\frac{- 8}{- 4}$ ( x -1)

y - 7 = 2 ( x - 1)

y - 7 = 2 x - 2

2 x - y + 5 = 0

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.

6 0

3 years ago