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3 years ago

11

My friend aliva said she want pie.but,it is 8 ft wide and 8 ft wide coast 199$what pie she get for less money 5ft 20$ 2ft 4$ 1ft

00.9$

2 answers:

alexdok [17]3 years ago

6 0

She could get C. 1ft $00.9

Hope that helps!

nignag [31]3 years ago

5 0

She could get c for 00.9

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PLEASE HELP !! ILL GIVE BRAINLIEST !!

kiruha [24]

Answer:the first one opn and qps

Step-by-step explanation:

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2 years ago

PLEASE HELP! ONLY GOT ONE CHOICE SO I WILL AWARD BRAINLIEST!!

viktelen [127]

Answer:

it's T it's not e because the middle bit is small

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2 years ago

onsider the following hypothesis test: H 0: 50 H a: > 50 A sample of 50 is used and the population standard deviation is 6. U

kondaur [170]

Answer:

a) z(e) > z(c) 2.94 > 1.64 we are in the rejection zone for H₀ we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) z(e) < z(c) 1.18 < 1.64 we are in the acceptance region for H₀ we can conclude H₀ should be true. we can conclude population mean is 50

c) 2.12 > 1.64 and we can conclude the same as in case a

Step-by-step explanation:

The problem is concerning test hypothesis on one tail (the right one)

The critical point z(c) ; α = 0.05 fom z table w get z(c) = 1.64 we need to compare values (between z(c) and z(e) )

The test hypothesis is:

a) H₀ ⇒ μ₀ = 50 a) Hₐ μ > 50 ; for value 52.5

b) Hₐ μ > 50 ; for value 51

c) Hₐ μ > 50 ; for value 51.8

With value 52.5

The test statistic z(e) ??

a) z(e) = ( μ - μ₀ ) /( σ/√50) z(e) = (2.5*√50 )/6 z(e) = 2.94

2.94 > 1.64 we are in the rejected zone for H₀ we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) With value 51

z(e) = ( μ - μ₀ ) /( σ/√50) ⇒ z(e) = √50/6 ⇒ z(e) = 1.18

z(e) < z(c) we are in the acceptance region for H₀ we can conclude H₀ should be true. we can conclude population mean is 50

c) the value 51.8

z(e) = ( μ - μ₀ ) /( σ/√50) ⇒ z(e) = (1.8*√50)/ 6 ⇒ z(e) = 2.12

2.12 > 1.64 and we can conclude the same as in case a

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2 years ago

An imaginary number has which of the following as a definition?

lyudmila [28]

Her is the definition of an imaginary number An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by its property i2 = −1. The square of an imaginary number bi is −b2. For example, 5i is an imaginary number, and its square is −25. Zero is considered to be both real and imaginary.
(Got that from google)

3 0

3 years ago

probability that cars have been assembled in a particular plant as follows: P(plant1)=20% , P(plant 2)=24% , P(plant 3.25% , P(p

Bogdan [553]

Answer:

16800/year

Step-by-step explanation:

Plant 1= 20%

Plant 2 = 24%

Plant 3 = 25%

Plant 4 = 31%

Total cars produced 100% = 1,200,000

Number of cars produced in plant 1 =

20% of 1,200,000 = 0.2 x 1,200,000 = 240,000 cars

Number of cars produced in plant 2 =

24% of 1,200,000 = 0.24 x 1,200,000 = 288,000 cars

Number of cars produced in plant 3 =

25% of 1,200,000 = 0.25 x 1,200,000 = 300,000 cars

Number of cars produced in plant 4 =

31% of 1,200,000 = 0.31 x 1,200,000 = 372,000 cars

Number of cars with no warranty claim in plant 1/year 223200

Number of cars with warranty claims in plant 1 + number of cars with no warranty claim in plant 1 = total number of cars produced in plant 1

X + 223200 = 240000

X = 240000 - 223200

X = 16800/year

number of cars with warranty claim in plant 1/ year is 16800

6 0

2 years ago