List the first 4 terms of the sequence 3n² + 1
2 answers:
<h2>
Answer: 4, 13, 28, 49</h2>
<h3>
Step-by-step explanation:</h3>
The first for terms of the series can be found by substituting the n for the term it is:
= 3(1)² + 1 , 3(2)² + 1 , 3(3)² + 1 ,3(4)² + 1
= 4, 13, 28, 49
Answer:
4, 13, 28, 49
Step-by-step explanation:
1st term = 3 × (1)² + 1 = 4
2nd term = 3 × (2)² + 1 = 13
3rd term = 3 × (3)² + 1 = 28
4th term = 3 × (4)² + 1 = 49
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