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Serggg [28]
3 years ago
15

List the first 4 terms of the sequence 3n² + 1​

Mathematics
2 answers:
avanturin [10]3 years ago
5 0
<h2>Answer:   4, 13, 28, 49</h2>

<h3>Step-by-step explanation:</h3>

The first for terms of the series can be found by substituting the n for the term it is:

= 3(1)² + 1​ , 3(2)² + 1​ , 3(3)² + 1​ ,3(4)² + 1​

= 4, 13, 28, 49

Ganezh [65]3 years ago
3 0

Answer:

4, 13, 28, 49

Step-by-step explanation:

1st term = 3 × (1)² + 1 = 4

2nd term = 3 × (2)² + 1 = 13

3rd term = 3 × (3)² + 1 = 28

4th term = 3 × (4)² + 1 = 49

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Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A.   3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 -  4 - 5

12 - 9

= 3

B.   3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

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C.   2(-2)² + 3(-2) -5 =

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8 - 11

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D.   2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

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