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Lera25 [3.4K]
3 years ago
13

What would be the answer for 24y =7

Mathematics
1 answer:
Marta_Voda [28]3 years ago
5 0

Answer:

y=\frac{7}{24}

Step-by-step explanation:

24y = 7

Our primary objective here is to get y on it's own side, without any numbers attached.

Since a 24 is attached to the y, we have to divide the 24y by 24.

24y=7

\frac{24y}{24} = \frac{7}{24}

Remember that whatever we do to one side, we MUST do to the other.

y=\frac{7}{24}

Since \frac{7}{24} can't be simplified, that would be our answer.

Please let me know if you need help with anything else. :)

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An article is bought for Rs. 125 what is the profit percentage?​
Aneli [31]

Step-by-step explanation:

Solution given;

cost price=Rs125

profit%=?

we have

profit%=[Selling price-cost price]/cost price×100%

=[selling price-Rs.125]/Rs 125×100% is your answer

7 0
3 years ago
Find the equation of the line that passes through the given points. (1, 4.5) and (3, 6)
Zanzabum

Answer:

y=0.75x+3.75

Step-by-step explanation:

The slope is

\frac{6 - 4.5}{3 - 1}  =   \frac{3}{4}

Substituting into point-slope form,

y - 6 = 0.75(x - 3)

y - 6 = 0.75x - 2.25

y = 0.75x + 3.75

6 0
2 years ago
Hurt just hurry and answer please
Luden [163]

Answer:

84

Step-by-step explanation:

Solve:

6*7= 42

42*2.00=84

Hope this helps!

3 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
I NEED THE ANSWER ITS DUE SOON !!! Points will be rewarded
DENIUS [597]

Answer:

Jaden added instead of subtracting 23 and 5

Step-by-step explanation:

3 0
3 years ago
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