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3 years ago

A dog eats 7 cans of food in 3 days. At this rate, how many cans of food does the dog eat in 3 + d days?

Mathematics

2 answers:

shutvik [7]3 years ago

8 0

It must be 15 as in 3 days he eats 7 so in 3 days + he eats 15

Dafna1 [17]3 years ago

6 0

The dog eats 7 cans plus d cans?
this any help?!!?

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3 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
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Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

3 years ago

Which choice names a radius of circle F?

ella [17]

Answer:

Step-by-step explanation:

The radius of a circle is the line segment from the centre of the circle to a point on the circle.

F is the centre of the circle, thus

FA, FE, FD, FC and FB are all radii of the circle

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3 years ago

Find the area of the shaded region.

satela [25.4K]

Answer:

Step-by-step explanation:

area of big triangle is 36

area of small triangle is 20

area of shaded is 36 - 20=16

4 0

3 years ago

IM GIVING BRAINLIEST!!!PLEASE HELP!!!I JUST KNOW ITS NOT A!!!

zmey [24]

Answer:

C. In y^2-y=6, 6 should have been subtracted on both sides first.

Step-by-step explanation:

It is a quadratic equation so you subtract the 6 and create

y^2-y-6=0

Then you factor it to:

(y-3)(y+2)=0

The solutions then are:

y-3=0, y=3 and y+2=0, y=-2

{-2,3}

4 0

3 years ago