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cluponka [151]
3 years ago
10

The graph below shows an airplane's speed over a period of time. Describe the events.

Mathematics
1 answer:
NemiM [27]3 years ago
8 0

Answer:

The airplane gains speed when it takes off. Then it begins to lose speed at the same rate. The plane then stays at the same speed the rest of the time.

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What is the answer to this question I’m stumped.
romanna [79]

Answer:

6x = 16

Step-by-step explanation:

We can write this as a proportion

6         8

---- = ----------

2         x

Using cross products

6x = 2*8

6x = 16

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the length of a rectangle is 6 cm more than three times the width of the perimeter of the rectangle is 36 cm, what are the dimen
Free_Kalibri [48]
2cm squared is the answer
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Step-by-step explanation:

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~PLEASE HELP ASAP OFFERING 10 POINTS~
Marina CMI [18]
T = c + cb
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(t - c)/c = b
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3 years ago
Find an asymptote of this conic section. 9x^2-36x-4y^2+24y-36=0
ki77a [65]
We will begin by grouping the x terms together and the y terms together so we can complete the square and see what we're looking at. (9x^2-36x)-(4y^2+24y)-36=0.  Now we need to move that 36 over by adding to isolate the x and y terms.  (9x^2-36x)-(4y^2+24y)=36.  Now we need to complete the square on the x terms and the y terms.  Can't do that, though, til the leading coefficients on the squared terms are 1's.  Right now they are 9 and 4.  Factor them out: 9(x^2-4x)-4(y^2-6y)=36.  Now let's complete the square on the x's. Our linear term is 4.  Half of 4 is 2, and 2 squared is 4, so add it into the parenthesis.  BUT don't forget about the 9 hanging around out front there that refuses to be forgotten.  It is a multiplier.  So we are really adding in is 9*4 which is 36.  Half the linear term on the y's is 3.  3 squared is 9, but again, what we are really adding in is -4*9 which is -36.  Putting that altogether looks like this thus far: 9(x^2-4x+4)-4(y^2-6y+9)=36+36-36.  The right side simplifies of course to just 36.  Since we have a minus sign between those x and y terms, this is a hyperbola.  The hyperbola has to be set to equal 1.  So we divide by 36.  At the same time we will form the perfect square binomials we created for this very purpose on the left: \frac{(x-2)^2}{4}- \frac{(y-3)^2}{9}=1.  Since the 9 is the bigger of the 2 values there, and it is under the y terms, our hyperbola has a horizontal transverse axis.  a^2=4 so a=2; b^2=9 so b=3.  Our asymptotes have the formula for the slope of m=+/- \frac{b}{a} which for us is a slope of negative and positive 3/2.  Using the slope and the fact that we now know the center of the hyperbola to be (2, 3), we can solve for b and rewrite the equations of the asymptotes.  3= \frac{3}{2}(2)+b give us a b of 0 so that equation is y = 3/2x.  For the negative slope, we have 3=- \frac{3}{2}(2)+b which gives us a b value of 6.  That equation then is y = -3/2x + 6.  And there you go!
8 0
3 years ago
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