The possible outcomes for 1 HEAD and 3 TAILS are
HTTT
THTT
TTHT
TTTH
Assuming the coin is a fair coin, we have:
Probability of tossing head is 0.5
Probability of tossing tail is 0.5
Probability of tossing the coin four times for each outcome combination listed above is
HTTT = 0.5×0.5×0.5×0.5 = 0.0625
THTT = 0.5×0.5×0.5×0.5 = 0.0625
TTHT = 0.5×0.5×0.5×0.5 = 0.0625
TTTH = 0.5×0.5×0.5×0.5 = 0.0625
Hence, probability of getting three tails and one head from 4 tossing is
4×0.0625 = 0.25
Answer:
Here is a similar question attached with.
Option (b) that is 2005 is the right choice.
Step-by-step explanation:
Given:
An equation in slope intercept form.
Where
= number of years
Comparing from the standard slope intercept form.

y-intercept value
According to the question the predicted winning speed
mph
Plugging the value of
in slope intercept form, we will calculate the
(number of years) and then we will add this with
.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Finally the year would be
So in year 2005 the winning speed is predicted to be 7.16 mph.
Any number of -4 and past that is lower than -3. (-4, -5, -6, -7, -8, -9)
Solution:
we are given that
Don walked 3 3/5 miles on Friday
It can be re-written as
miles
3 5/8 miles on sunday.
It can be re-written as
miles
an d He walk 3.7 miles on satarday.
The distances from least to greatest is 3.6, 3.625, 3.7
or
The distances from least to greatest is
miles,
miles, 3.7 miles.
12n-3=7(n-4)+5n
12n-3=7n-28+5n
12n-3=12n-28
0n=-25
n=undefined. As a result, this answer has No solution. Hope it help!