<span>s in (-oo:+oo)
(1/3)*s+14 = 26 // - 26
(1/3)*s-26+14 = 0
1/3*s-12 = 0 // + 12
1/3*s = 12 // : 1/3
s = 12/1/3
s = 36
s = 36</span>
Answer:
its 60
Step-by-step explanation:
i took the test
Answer:
C)
Step-by-step explanation:
Because -8.2+(-4.1)=-8.2-4.1=-12.3.
Answer: x=5
5x-3 (x-3)= -6 +6x -5
5x -3x +9 =-6 +6 x -5
Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
