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Volgvan
3 years ago
10

Simplify (3 x 22) / 6 + [28 - (4)^2]

Mathematics
1 answer:
Elodia [21]3 years ago
3 0

Answer

564

Step-by-step explanation:

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Divide 2x^4+3x^3-5x+6 by x^2+3x-2 .
Anni [7]

2x^4 + 3x^3 - 5x + 6  ÷ x^2 + 3x - 2

= 2x^6 + 3x^5 − 2x^3 − 2x^2 + 6/ x^2

4 0
3 years ago
Jared is standing on the roof of a 100 meter building doing some surveying. He spots a delivery truck at an angle of depression
just olya [345]
1st :The angle of depression 30° = the angle of elevation (from the truck to the height of the building.

2nd :
cos 30° = (adjacent side)/(hypotenuse)
cos 30° = x/100, but cos 30°= (√3)/2

(√3)/2 = x/100 and x = (100√3)/2

and x = (50.√3) = 86.60 m

8 0
4 years ago
Read 2 more answers
Jill charges an hourly rate for babysitting one or two children. Kara charges a lower hourly
rodikova [14]

<u>Options</u>

Which statement is true:

a) Jill will make less money if they each work 4 hours.

b) Jill's hourly rate is $3 more than kara's.

c) Kara charges $14 and hour for babysitting two children.

d) Kara's fee for the second child is $5.

Answer:

(D)Kara's fee for the second child is $5.

Step-by-step explanation:

\left|\begin{array}{c|c|c}$Time(hr)&$Jill: Cost for Two Children& $Kara: Cost for Two Children\\-----&------&-----\\1&11&14=9+5\\2&22&23=9(2)+5\\3&33&32=9(3)+5\end{array}\right|

From the table above,

Jill Charges an hourly rate of $11

Kara charges an hourly rate of $9 and an additional $5 charge for more than one child. Therefore, the statement that is true is Option D.

Kara's fee for the second child is $5.

All other options are incorrect.

<u>Check</u>

Option A: In four hours, Jill will make $44 while Kara will make $41

Option B: Jill's hourly rate is $2 more than Kara's, NOT $3.

Option C: Kara charges $9 an hour, NOT $14.

7 0
3 years ago
-8(17-12)/-2(8-(-2))
quester [9]
200 according to google calculator
7 0
3 years ago
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What basic trigonometric identity would you use to verify that (sin2x + cos2x)/cosx=secx
Oksana_A [137]

Answer:

Step-by-step explanation:

sin(2x) = 2 sin(x) cos(x) cos(2x) = cos2(x) – sin2(x) = 1 – 2 sin2(x) = 2 cos2(x) – 1. Now I am not sure if this is right but I remember another similar formula. Here is the correct formula cot x = cos x / sin x

2 ) ( sin² x + cos² x ) / cos x = sec x

1/cos x = sec x

sec x = sec x

cos² x + sin² x = 1

7 0
3 years ago
Read 2 more answers
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