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saul85 [17]
3 years ago
12

Questions

Biology
1 answer:
Marat540 [252]3 years ago
4 0

The decay of uranium isotopes is used to provide information about the age of Earth.

<h3>Explanation:</h3>

Isotopes of Uranium U-232, U-233 , U-234 , U-235 , U-236 , U-238 are used as fuel in nuclear reactors or as explosives for nuclear weapons. Uranium 238 is not very radioactive and it constitutes for nearly 99.3% of natural uranium on Earth and has the longest lifetime: its period is 4.5 billion years, about the age of Earth.

Use of radiometric dating techniques help in defining the age of substances (natural or man-made) using the known decay rates of radioactive elements. Each element has an  individual decay rate and half life time.

Two Uranium isotopes (U-238 and U-235) are used for radiometric dating. Both the isotopes have different decay rates and half life period. Both are unstable and radioactive. Since two different isotopes produce two different decay clocks (one as a reference to other), it is beneficial in accurately determining the age of samples. The age of earth (rocks or other natural elements) can be easily determined using Uranium isotopes.

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How are the studies performed on rainbow trout ( Oncorhynchus mykiss) and the moss Pleurozium schreberi and the desert shrub Atr
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Answer:

Both studies support the concept that species operate within a narrow optimum temperature range and are coupled to enzymatic activity.

Explanation:

The studies shown in the question above started from the same concept to establish the scientific experiment and had the same objective related to the investigation as temperature changes in the environment where these organisms live influences the enzymatic activity and, therefore, the functioning of their organism, being able to including modifying the environment around them. In summary, we can say that the studies sought to support the concept that species operate within a narrow range of optimal temperature and are coupled with enzymatic activity.

4 0
3 years ago
Which statement regarding the relative ages of rocks and events is
taurus [48]

Answer:

C. Faults are younger than the youngest layer they cut through.

Explanation:    

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<em>B. A fold is older than the oldest rock layer it contains. </em>WRONG. First, layers are set, and then, it occurs the folding. The folding is always younger than the involved layers.  

<em>C. Faults are younger than the youngest layer they cut through.</em> RIGHT. A fault is a cut through different layers that occurs when the sedimentary rock breaks transversally. It occurs always after the sedimentary rock is already formed. So the fault is always younger than all the layers it cuts through.

D. Rock layers that have been overturned are oldest from the base to the surface. WRONG. If <u>overturned</u>, according to the superposition low, layers are oldest from the surface to the base. Superposition law states that during the sedimentary rock formation, the oldest layer is always that one at the bottom, while the younger layer is the higher one.

4 0
3 years ago
Now assume that the population of butterflies sampled in question above is in Hardy-Weinberg equilibrium. Also assume that the s
horsena [70]

Complete question:

A sample of butterflies contained 50% yellow-winged individuals and 50% black-winged individuals. In this species, wing color is determined by a single gene with two alleles, and the allele for black is dominant. Which of the following statements about the allele frequencies in the sample would most likely be true?  Do not assume that this sample was obtained from a population in genetic equilibrium.

a)The frequency of the yellow allele is greater than that of the black allele.

b)The allele frequency of yellow is 3 times the allele frequency of black.

c)The allele frequency of yellow is twice the allele frequency of black.

d)The allele frequencies of black and yellow are equal.

e) The allele frequency of black is greater than the allele frequency of yellow.

2.Now assume that the population of butterflies sampled in question above is in Hardy-Weinberg equilibrium. Also assume that the sample is random and large enough that the allele frequencies in the sample equal the allele frequencies in the population.  What is the frequency of the allele for a) yellow wings in the population? Assuming Hardy-Weinberg equilibrium in question 1, what would the correct answer be and why?

Answer:

  • a)The frequency of the yellow allele is greater than that of the black allele.
  • f(b) = q = 0.71

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

Download pdf
5 0
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