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4 years ago

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Given EAB and DCB are two right triangles. The figurebhas BED=BDE. point b is the midpoint of segment AC. prove EAB= DCB.

1 answer:

Ronch [10]4 years ago

3 0

Answer:

EAB= DCB

Step-by-step explanation:

Since EAB and DCB are two right triangles then the figure ACDE is rectangular. since the total sum of rectangular 360° there is no options except to be rectangular. If the figure ACDE is rectangular then the two sides AE & CD are equal. Since Point b is midway point the two sides are also equal.

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Find the 14th term of the geometric sequence 5 -10 20

Anna [14]

Answer:

a14 = -40,960

Step-by-step explanation:

The sequence has a first term of 5 and a common ratio of -10/5 = -2, so the n-th term is given by ...

an = a1·r^(n-1)

an = 5·(-2)^(n-1)

The 14th term is then ...

a14 = 5·(-2)^(14-1) = -5·2^13 = -5·8192

a14 = -40,960

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4 years ago

Read 2 more answers

X ≥ -2 is the inequality of the graph below<br><br> True or False

Pie

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3 years ago

Two kinds of perfume are packaged in square pyramidal bottles. Perfume A is packaged in a bottle with a base of 3 inches square

kondor19780726 [428]

Answer:

The bottle of perfume A contains more glass

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four triangular faces

step 1

Find the surface area of Perfume A

$SA=3^{2} +4[\frac{1}{2}(3)(2.5)]=24\ in^{2}$

step 2

Find the surface area of Perfume B

$SA=2.5^{2} +4[\frac{1}{2}(2.5)(3)]=21.25\ in^{2}$

step 3

Compare the surface areas

$24\ in^{2}>21.25\ in^{2}$

therefore

The bottle of perfume A contains more glass

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Step-by-step explanation:

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