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3 years ago

Explain, in words, how you can identify a perfect square trinomial whose leading coefficient is 1

1 answer:

4 0

When the leading coefficient is 1,
If the constant ( c term) is a perfect square and the b term is 2* the square root of the c term.
Ex.
x*2 + 10x + 25
2*5 = 10 5*5=25
Ex.
x^2 - 12x + 36
2 * -6 = -12 6*6=36

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Write "yes" or "no" to state whether or not the given side lengths would form a right triangle.

Slav-nsk [51]

Answer: No

Step-by-step explanation:

To find out if it is a right triangle then use the formula a^2 + b^2 = c^2 where a and b are the legs which are the two small sides and c is the hypotenuse the longest side. Input the values for a, b, and c and solve.

a = 12

b = 16

c= 25

12^2 + 16^2 = 25^2

144 + 256 = 625

400 = 625

This means that it is not a right angle because 400 does not equal to 625.

7 0

3 years ago

Solve the equation E = IR for I

alexgriva [62]

Answer:

$I=\frac{E}{R}; R\neq 0$

Step-by-step explanation:

$E=IR\\\\IR=E\\\\\frac{IR=E}{R}\\\\ \boxed{I=\frac{E}{R}; R\neq 0}$

Hope this helps.

3 0

3 years ago

Y-3=5(x-2) what are the intercepts t of x and y x=(_,_) y=(_,_)

yan [13]

$The\ x\ intercept\ is\ (\frac{7}{5}, 0)$

The y intercept is (0, -7)

Solution:

Given equation is:

y - 3 = 5(x - 2)

Find the x intercept

Substitute y = 0 in given equation

$0-3=5(x-2)\\\\-3=5x - 10\\\\5x = -3 + 10\\\\5x = 7\\\\x = \frac{7}{5}\\\\Thus\ the\ x\ intercept\ is\ (\frac{7}{5}, 0)$

Find the y intercept:

Substitute x = 0 in given equation

$y - 3 = 5(0-2)\\\\y - 3 = -10\\\\y = -10 + 3\\\\y = -7$

Thus the y intercept is (0, -7)

4 0

3 years ago

What is the result of dividing 2x3 – 3x2 – 17x + 30 by x + 3?

Anna71 [15]

2x^3 - 3x² - 17x + 30 | x + 3
________________________ 
2x^3 + 6x² _________| 2x² - 9x + 10 
_____-9x² - 17x ____ | 
_____-9x² - 27x ____ | 
_________ 10x + 30 _| 
_________ 10x + 30 _| 
________ _____ __0 _| 

Ans : 2x² - 9x + 10

BRAINLIEST PLS!!!!

8 0

3 years ago

Find the x- and y-intercept of the line.

OlgaM077 [116]

$-3x+9y=18 \\ \\
\hbox{x-intercept - y=0:} \\
-3x+9 \times 0=18 \\
-3x=18 \ \ \ |\div (-3) \\
x=-6 \\ \\
\hbox{y-intercept - x=0:} \\
-3 \times 0+9y=18 \\
9y=18 \ \ \ |\div 9 \\
y=2$

The x-intercept is -6 and the y-intercept is 2. The answer is A.

8 0

4 years ago