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Ray Of Light [21]
2 years ago
8

Explain, in words, how you can identify a perfect square trinomial whose leading coefficient is 1

Mathematics
1 answer:
liberstina [14]2 years ago
4 0
When the leading coefficient is 1,
If the constant ( c term) is a perfect square and the b term is 2* the square root of the c term.
Ex.
x*2 + 10x + 25
2*5 = 10 5*5=25
Ex.
x^2 - 12x + 36
2 * -6 = -12 6*6=36
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Brenda took out a personal loan for $12,000 at an interest rate of 12% compounded monthly. She made arrangements to pay the loan
iragen [17]

Answer: her monthly payments would be $267

Step-by-step explanation:

We would apply the periodic interest rate formula which is expressed as

P = a/[{(1+r)^n]-1}/{r(1+r)^n}]

Where

P represents the monthly payments.

a represents the amount of the loan

r represents the annual rate.

n represents number of monthly payments. Therefore

a = $12000

r = 0.12/12 = 0.01

n = 12 × 5 = 60

Therefore,

P = 12000/[{(1+0.01)^60]-1}/{0.01(1+0.01)^60}]

12000/[{(1.01)^60]-1}/{0.01(1.01)^60}]

P = 12000/{1.817 -1}/[0.01(1.817)]

P = 12000/(0.817/0.01817)

P = 12000/44.96

P = $267

7 0
2 years ago
Need urgent help in mathematics!! Will mark brainliest!!!!
Nataly [62]

₇P₅ is a permutation. you can find this setting in the statistics menu of your scientific calculator (i think).

If you don't have a scientific calculator, you can use the following formula:

nPr = \frac{n!}{(n - r)!}

₇P₅  = \frac{7!}{(7 - 5)!}

     = \frac{7}{2!}

     = \frac{7 * 6 * 5 * 4 * 3 * 2!}{2!}

     = 7 * 6 * 5 * 4 * 3

    = 2520

Answer: C

3 0
3 years ago
Read 2 more answers
Which Expression can be used to solve 3/5÷7/10A. 5/3*7/10B. 5/3*10/7C. 3/5*10/7D. 3/5*7/10
Harrizon [31]

Which Expression can be used to solve 3/5÷7/10



A. 5/3*7/10

B. 5/3*10/7

C. 3/5*10/7

D. 3/5*7/10​

This expression 3/5÷7/10 means

An option to solve the expression is inverting the fraction that is dividing and going to multiply

3/5 x 10/7 C.

________________-

Verification

A and D are the same

6 0
9 months ago
Round 0.885 to the nearest hundredths.
andrew-mc [135]
0.885 rounded to the nearest hundreds would be 0.89
5 0
2 years ago
The lengths of two sides of a triangle are 12 ft and 13 ft. find the range of possible lengths for the third side
mihalych1998 [28]
Let x be the length of third side.
12 + x > 13
x > 1-------------(1)
13 + x > 12
x > -1 ------------(2)
by combining (1) and (2)
we have x > -1

3 0
2 years ago
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