We know that
the graphic has two intervals
x>1------> (1,∞)
equation of second order
and
x<=1------> (-∞, 1]
equation of a line
therefore
<span>The only option that meets these requirements is option A
</span>
the answer is
the option A
(g₀f)(x)=g(f(x))
=g(2x-2)
=5(2x-2)^2-3
=5(4x^2-8x+4)-3
=20x^2-40x+17
Answer:
-1b-6
Step-by-step explanation:
4.3 x 10⁻⁵ Liters
0.043 mL
4.3 x 10⁻² mL
This ordered pair is not a solution for the given equations. We can tell this by plugging in to each of them and seeing that it does not provide a true statement for both. It does work for the first, but is not an intersection due to it not working for each.
4x - 3y = 30
4(6) - 3(-2) = 30
24 + 6 = 30 (TRUE)
3x + 2y = 22
3(6) + 2(-2) = 22
18 - 4 = 22
16 =/= 22 (FALSE)
