<span>Multiply one of the equations so that both equations share a common complementary coefficient.
In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
You can multiply the 1st equation by -2/5 to allow cancelling the a term.
You can multiply the 1st equation by 5/3 to allow cancelling the b term.
You can multiply the 2nd equation by -2.5 to allow cancelling the a term.
You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that.
5a + 3b = –9
2a – 5b = –16
5*(5a + 3b = -9) = 25a + 15b = -45
3*(2a - 5b = -16) = 6a - 15b = -48
Then add the equations
25a + 15b = -45
6a - 15b = -48
=
31a = -93
a = -3
And then plug in the discovered value of a into one of the original equations and solve for b.</span>
Answer:
To see if a table of values represents a linear function, check to see if there's a constant rate of change. If there is, you're looking at a linear function!
Step-by-step explanation:
Answer:
Step-by-step explanation:
let x be the population
so we have ,
2x= 6h
?= 3 days or 3×24h
by cross multiplication we have
2x× 72h= 6h×?
?= 2x×72/6 = 24x
So, in three days the bacteria will b 24 times current population.
There we have an information of two functions 
Using this two functions , we need to find the composition of functions (h\circ g)(t).
The composition of two functions h and g is the new function , by performing g first and then performing h.
Composition of h and g (t) = 
First plugin the value of 
We know that , we need to find h(3t+3),
That is, to replace t by 3t+3,
Now distribute 2 into 3t+3,
Now plug in 
Thus the solution is (D). 
$5,796 is how much it would be. hope it helps
