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shtirl [24]
3 years ago
8

Jim asked his baseball team how many glasses of milk and how many glasses of water each player drinks per day. The line plots be

low show his data.
Mathematics
1 answer:
stira [4]3 years ago
4 0
Hzhzhzhzhabzhsuxuzhbxbdbdbsgyyzyz
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Complete the table shown below.<br><br> table showing function<br><br> x = <br><br> y = <br><br> z =
PtichkaEL [24]

Answer:

x = 1

y = 1

z = 1

Step-by-step explanation:

hope it will help you

8 0
3 years ago
What is -12.5-8.3<br><img src="https://tex.z-dn.net/?f=12.5%20-8.3" id="TexFormula1" title="12.5 -8.3" alt="12.5 -8.3" align="ab
Mama L [17]

If it’s a negative equation is should be -20.8 otherwise it’s 4.2

5 0
3 years ago
Read 2 more answers
What is the solution to this equation?
Usimov [2.4K]
-0.5 n^2=-18
n^2= 36
n= sqrt (36)=6 or -6

Hope this can help.
7 0
3 years ago
Read 2 more answers
How to determine if the columns of a matrix are linearly independent?
astra-53 [7]
Let's consider an arbitrary 2x2 matrix as an example,

\mathbf A=\begin{bmatrix}\mathbf x&\mathbf y\end{bmatrix}=\begin{bmatrix}x_1&y_1\\x_2&y_2\end{bmatrix}

The columns of \mathbf A are linearly independent if and only if the column vectors \mathbf x,\mathbf y are linearly independent.

This is the case if the only way we can make a linear combination of \mathbf x,\mathbf y reduce to the zero vector is to multiply the vectors by 0; that is,

c_1\mathbf x+c_2\mathbf y=\mathbf 0

only by letting c_1=c_2=0.

A more concrete example: suppose

\mathbf A=\begin{bmatrix}1&2\\4&8\end{bmatrix}

Here, \mathbf x=\begin{bmatrix}1\\4\end{bmatrix} and \amthbf y=\begin{bmatrix}2\\8\end{bmatrix}. Notice that we can get the zero vector by taking c_1=-2 and c_2=1:

-2\begin{bmatrix}1\\4\end{bmatrix}+\begin{bmatrix}2\\8\end{bmatrix}=\begin{bmatrix}-2+2\\-8+8\end{bmatrix}=\mathbf 0

so the columns of \mathbf A are not linearly independent, or linearly dependent.
8 0
3 years ago
What is the value of x?​
guajiro [1.7K]

Answer:

x ≈ 8.66

Step-by-step explanation:

Using the sine ratio in the right triangle

sin60° = \frac{opposite}{hypotenuse} = \frac{x}{10}

Multiply both sides by 10

10 × sin60° = x, thus

x ≈ 8.66 ( to 2 dec. places )

4 0
3 years ago
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