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Trava [24]
3 years ago
14

PLEASE HELP!!!!! Write the absolute value inequality in the form

Mathematics
2 answers:
Elena-2011 [213]3 years ago
7 0

Answer:

|x - 1 |> 6,

Step-by-step explanation:

First we find the distance between the two points

-5 to 7

7 - -5 =7+5 = 12

We find 1/2 that distance

12/2 = 6

So we are looking for a greater-than inequality  because we are looking for the outsides because we want a less than and a greater than

|x - b |> c,

The center is 6 to that is c

|x - b |> 6,

To find the value of b

Let x = 7

7 -b =6

b=1

|x - 1 |> 6,

We can check by using -5

|-5 - 1 |> 6,

Stells [14]3 years ago
7 0

Answer:

|x - 1| > 6

Step-by-step explanation:

x < -5 or x > 7

b is the centre:

(-5+7)/2 = 1

c is the distance from the centre

7 - 1 = 6

Or

1 - (-5) = 6

Since it's an or case, inequality with the modulus would be >

|x - 1| > 6

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1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

<u>1. 5 in and 1/3 in</u>

Here,

Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2

<u>2. 5 in and 4/3 in</u>

Here,

l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2

<u>3. 5/2 in and 4/3 in</u>

let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2

<u>4. 7/6 in and 6/7 in</u>

<u>Let</u>

l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2

<u>Hence,</u>

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

8 0
3 years ago
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Answer:

The correct answer would be 10ft

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He traveled 227.5 miles. 
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Will give brainliest if correct.
Nataly [62]

Answer:

The answer would be, 81cm.

Step-by-step explanation:

36÷4=9

9×9=81

8 0
3 years ago
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