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3 years ago

What is the value of s? ? units

Mathematics

2 answers:

Anton [14]3 years ago

8 0

Pythagoras theorem:
hypotenuse²=leg₁²+leg₂²

Data:
leg₁=8
leg₂=15
hypotenuse=s

hypotenuse²=(8)²+(15)²
hypotenuse²=64+225
hypotenuse²=289
hypotenuse=√289
hypotenuse=17

Answer: s=17

Evgesh-ka [11]3 years ago

7 0

By Pythagoras' Theorem.

s² = 8² + 15²

s²= 64 + 225

s² = 289

s = √289

s = 17

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$\bold{\huge{\underline{ Solution }}}$

<h3>Analysis of graph :-</h3>

We have given one graph which is plot between distance and time. where time is in minutes and distance is in seconds.

According to the graph

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For next 6 minute that is from 16 to 21 minutes ( D to E) . Again, There distance is increasing with time .
Again For next 4 minutes that is 21 to 25 minutes , they are moving with constant velocity .

<h3>Let's Begin :-</h3>

1) Between O and A

The marellize and wally when moving between O to A , The distance is constantly increasing with time.
The graph is Straight line

2) Between A and B

The marellize and wally when moving between A to B, The distance remains the same with time that is they moving with constant speed.
The graph is constant or steady

3) Between B to C

The marellize and wally when moving between B to C, The distance is constantly decreasing with time .
The graph is straight line but it follows decreasing function .

4) For covering the First 6 km ,

According to the graph,

For covering first 6 km, They took 3 minutes.

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D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.

Step-by-step explanation:

We will test the hypothesis on the difference between means.

We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).

Then, the difference between means is:

$M_d=M_1-M_2=18.2-15.9=2.3$

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{2.3-(0)}{1.1}=2.09$

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.

This is approximately 2 standards deviation (z=2).

The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.

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