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3 years ago

Helpppp quickkkkk plzz

Mathematics

2 answers:

Valentin [98]3 years ago

7 0

The Pythagorean theorem proves a triangle is a right triangle if the square of the height plus the square of the base equals the square of the hypotenuse ( A^2 + b^2 = c^2)
So the answers should be:

1. Side lengths

2. a^2 + b^2 = c^2

3. is a right triangle

kozerog [31]3 years ago

5 0

The Pythagoras Theorem is a^2 +b^2 = c^2 if this is true then you have a right triangle. So I think they are looking for side lengths in the first box.

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Find the number of 3-digit numbers formed using the digits 1 to 9, without repetition, such the numbers either have all digits l

Tasya [4]

Answer: 120

Step-by-step explanation:

The total number of digits from 1 to 9 = 10

The number of digits from less than 5 (0,1,2,3,4)=5

Since repetition is not allowed so we use Permutations , then the number of 3-digit different codes will be formed :-

$^5P_3=\dfrac{5!}{(5-3)!}=\dfrac{5\times4\times3\times2!}{2!}=5\times4\times3=60$

The number of digits from greater than 4 (5,6,7,8,9)=5

Similarly, Number of 3-digit different codes will be formed :-

$^5P_3=60$

Hence, the required number of 3-digit different codes = 60+60=120

3 0

3 years ago

Can someone please help?

kifflom [539]

Standard form means, move the variables to the left-hand-side and leave the constant all by herself on the right-hand-side, usually sorting the variables, so"x" goes first.

now, there's a denominator, we can do away with it, by simply multiplying both sides by the denominator, so let's do so,

$\bf y=-\cfrac{2}{3}x+7\implies \boxed{3}\cdot y=\boxed{3}\cdot \left( -\cfrac{2}{3}x+7 \right)\implies 3y=-2x+21
\\\\\\
\stackrel{standard~form}{2x+3y=21}$

5 0

3 years ago

What is the percent of change?

Simora [160]

Hi there!

In order to find the percent of change, we need to divide 3/8 by 7/8.

$\frac{3}{8} \div \frac{7}{8} = \frac{3}{8} \times \frac{8}{7} = \frac{3}{7} = 43\%$
Hope this helps!

5 0

3 years ago

Factorise (x+3)²-25<br>help meeeeee

bearhunter [10]

....................

4 0

3 years ago

Read 2 more answers

David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below.

Vikentia [17]

Answer:

Given Polynomial:

$80b^4-32b^2c^3+48b^4c$

Factors of Coefficient of terms

80 = 5 × 16

32 = 2 × 16

48 = 3 × 16

Common factor of the coefficient of all term is 16.

Each term contain variable. So the Minimum power of b is common from all terms.

Common from all variable part comes b².

So, Common factor of the polynomial = 16b²

⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )

⇒ 16b² ( 5b² - 2c³ + 3b²c )

Therefore, Statements that are true about David's word are:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property

8 0

3 years ago

Read 2 more answers