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Maru [420]
3 years ago
11

Please help: solve for x

Mathematics
1 answer:
klemol [59]3 years ago
8 0

Answer:

x=11

Step-by-step explanation:

This is because 6+10=16 so your line with x must equal 16. You subtract 5 from 16 to get 11. This is your answer.

You might be interested in
Fire Fighters are attempting to rescue people from the 3rd floor of a building. The
Daniel [21]

Answer:

If it's where they can get to the building I think it's 15

Step-by-step explanation:

Cause 10 plus 5 and if that can reach where they are able to get in I'd assume it would be 15

I'm not a genius or anything so don't rely on my answer

7 0
2 years ago
Need help ON THESE TOO PLEASE WILL MARK BRAINLY
LenKa [72]

Answer:

1)

angle 2WZX = angle ZYX ( Since all angles and sides of a rhombus are equal)

ZYX = 2 x 29.5

59

2)

4x - 10 =90 (since all angles of a rhombus intersect at 90°)

x=90+10/4

x=100/4

x=25

hope this helps

5 0
3 years ago
Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim
tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10959}{25} =438.36

Sum of squares of differences = 175413.76

S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49

Population mean, μ = 425 mg/L

Sample mean, \bar{x} = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813

Now, t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108

Since,                        

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0
3 years ago
What is the answer for this question
Pavlova-9 [17]

Answer:

option d. is the correct answer

5 0
3 years ago
F (n) = 65 - 100n<br> f (39) =
yan [13]

f(39)=65-100(39)

65-3900

= -3835

6 0
2 years ago
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