Answer:
Step-by-step explanation:
Given
Height of building is ![h=110\ ft](https://tex.z-dn.net/?f=h%3D110%5C%20ft)
Initial upward velocity ![u=23\ ft/s](https://tex.z-dn.net/?f=u%3D23%5C%20ft%2Fs)
height of object is given by
![z(t)=ut+\frac{1}{2}gt^2](https://tex.z-dn.net/?f=z%28t%29%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
but building is already at a height of 110 ft so z(t) must be given by
![Z(t)=ut+\frac{1}{2}(-g)t^2+110](https://tex.z-dn.net/?f=Z%28t%29%3Dut%2B%5Cfrac%7B1%7D%7B2%7D%28-g%29t%5E2%2B110)
![Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2](https://tex.z-dn.net/?f=Z%28t%29%3D23%5Ctimes%20t-%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.8%5Ctimes%20t%5E2)
![Z(t)=-16t^2+23t+110](https://tex.z-dn.net/?f=Z%28t%29%3D-16t%5E2%2B23t%2B110)
Time when it hits is given by when Z(t)=0[/tex]
![-16t^2+23t+110=0](https://tex.z-dn.net/?f=-16t%5E2%2B23t%2B110%3D0)
![t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-23%5Cpm%20%5Csqrt%7B%2823%29%5E2-4%5Ctimes%20%28-16%29%5Ctimes%20110%7D%7D%7B2%5Ctimes%20%28-16%29%7D)
![t=\frac{-23\pm 87}{-32}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-23%5Cpm%2087%7D%7B-32%7D)
![t=3.43\ s](https://tex.z-dn.net/?f=t%3D3.43%5C%20s)
Answer is -h = -51 (download photomath)
Answer:
9^5
Step-by-step explanation:
the number you're multiplying stays the same and you add your powers I believe.
so it's basically 9•1 and the ^2+^3=^5
The answer to the question is x = 0