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2 years ago

What multiplication product is represented by this grid

Mathematics

1 answer:

vlabodo [156]2 years ago

7 0

Answer: 0.07 x 5

There are 35 colored out of the 100 = 35%

35% = 0.35 = 0.07 x 5

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X/5 + 1 = 10<br><br> It’s number 11

shusha [124]

Answer:

X = 45

Step-by-step explanation:

7 0

2 years ago

Brendon had total job benefits of $39,500 last year. He was required to wear a shirt with the company logo on it for work that h

san4es73 [151]

Answer:

Step-by-step explanation:

It is correct

6 0

1 year ago

Read 2 more answers

A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find

Ratling [72]

Answer:

Area of the garden:

$\begin{equation*} 398.93\text{ ft}^2 \end{equation*}$

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

$r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}$

Let's now go ahead and determine the area of the semicircle using the below formula;

$A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2$

Let's also determine the area of the rectangle;

$A_r=l*w=23*14=322\text{ ft}^2$

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

$\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}$

Therefore, the area of the garden is 398.93 ft^2

8 0

11 months ago

Precalc experts! I need your help!

mars1129 [50]

Answer:

$f(x)\to 1$

Step-by-step explanation:

The function approaches its horizontal asymptote in both directions as the magnitude of x gets large. The limit is y = 1.

7 0

3 years ago

F(n) = f(n – 1) + f(n – 2); f(1) = 2; f(2) = 1.

Alex Ar [27]

f(n) is the nth term

Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)

The term just before nth term is f(n-1)

The term just before the (n-1)st term is f(n-2)

----------------

For example, let's say n = 3 indicating the 3rd term

n-1 = 3-1 = 2

n-2 = 3-2 = 1

So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.

f3) = third term

f(2) = second term

f(1) = first term

8 0

2 years ago