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2 years ago

ANYEONESSSSSSSSSS???

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

4 0

Answer:

C. 2

Step-by-step explanation:

To solve slope, the formula is $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ . 9-3 is 6 and 5-2 is 3. So simplify 6/3 to 2.

Hope it's correct!

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If f(×) = -2x+8, find f(3)

andrezito [222]

Answer:

f(3) = 2

Step-by-step explanation:

To evaluate f(3), substitute x = 3 into f(x), that is

f(3) = - 2(3) + 8 = - 6 + 8 = 2

4 0

2 years ago

Use the graph of the floor function to complete the statements. Over the interval , y = 2. For an input value of –1.5, the corre

nata0808 [166]

Answer:

over the interval [2,3)

for an input value of 1.5, the corresponding output value is -2

Step-by-step explanation:

3 0

2 years ago

Dont know how to calculate it

TEA [102]

Answer:

AB = 105

Step-by-step explanation:

Since ∠ A and ∠ B are equal then Δ ABC is isosceles with 2 congruent legs.

AC = BC , substitute values

6x - 7 = 5x + 7 ( subtract 5x from both sides )

x - 7 = 7 ( add 7 to both sides )

x = 14

Then

AB = 7x + 7 = 7(14) + 7 = 98 + 7 = 105

6 0

1 year ago

You are sitting at the edge of the Grand Canyon admiring the view when you notice a tour group at the bottom of the canyon. You

ololo11 [35]

Answer:

7949.13 feet

Step-by-step explanation:

We are given that,

Angle of depression from the spot to the group = 39°

Height of Grand Canyon = 5000 feet.

So, we will get the following figure of a right triangle.

<em>As, 'in a right triangle, the angles and the sides can be written in trigonometric form'.</em>

We get, $\sin A=\frac{perpendicular}{hypotenuse}$

i.e. $\sin 39=\frac{5000}{x}$

i.e. $x=\frac{5000}{\sin 39}$

i.e. $x=\frac{5000}{0.629}$

i.e. x = 7949.13 feet

Thus, the line of sight distance is 7949.13 feet.

5 0

3 years ago

11/ 42 Marks

amm1812

Answer:

(a)x=128 degrees

(b) $\angle APD\neq 116^\circ$

Step-by-step explanation:

$\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ$

(a) Now:

$\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ$

(b)

$\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ$

$\angle APD\neq 116^\circ$

7 0

2 years ago