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vovikov84 [41]
3 years ago
7

What is the.least common multiple of 2 and 6

Mathematics
2 answers:
Burka [1]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Leya [2.2K]3 years ago
3 0

Answer:

The answer to this is: The Least Common Multiple of 2 and 6 is 6.

Step-by-step explanation:

Hope this helps :)

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What is D and R? Please answer I need help.
Setler79 [48]

Answer:

  31. D: {8, 4, 0, -4}; R: {2, -1}; yes

  32. D: {-1, 2, 7}; R: {-4, -3, -2, 0}; no

  33. D: {-4, -3, -1, 2, 3, 5}; R: {-3, -2, 0, 3, 5}; yes

  34. D: (-∞, ∞); R: (-∞, 4]; yes

  35. D: [0, 5]; R: [-2, 3]; no

Step-by-step explanation:

In this context, D means "domain" and R means "range." The domain of a function is the list of input values for which the function is defined. For ordered pairs, it is the first number of the pair. For an x-y table, it is the list of x-values. For a graph, it is the possible values of x.

A relation is a <em>function</em> only if there are no repeated values in the domain (2 or more outputs for the same input.)

The range of a function is the list of output values produced by the function. For ordered pairs, it is the second number of the pair. For an x-y table, it is the list of y-values. For a graph, it is the possible values of y.

__

31. D: {8, 4, 0, -4}

    R: {2, -1}

Function: yes

Domain and range values don't need to be repeated. Often, they're listed in order from lowest to highest. Here, we have listed them in order of occurrence in the function definition.

__

32. D: {-1, 2, 7}

      R: {-4, -3, -2, 0}

Function: no

__

33. D: {-4, -3, -1, 2, 3, 5}

     R: {-3, -2, 0, 3, 5}

Function: yes

__

34. D: (-∞, ∞)

     R: (-∞, 4]

Function: yes

__

35. D: [0, 5]

     R: [-2, 3]

Function: no . . . . . . there are 2 y-values for most x-values

4 0
3 years ago
A piling for a high-rise building is pushed by two bulldozers at exactly the same time. One bulldozer exerts a force of 1250 pou
Masja [62]
The forces result in a right triangle. To obtain the resultant force, one can simply use the Pythagorean theorem. 1250 lbf and 2650 lbf both act as the legs of the triangle. Obtaining the hypotenuse via the theorem would yield the resultant force. This is done below:

c^2 = a^2 + b^2
c^2 = (1250)^2 + (2650)^2
c = 2930.017 lbf

Therefore, the magnitude of the resultant force is approximately equal to 2930 lbf.
8 0
3 years ago
Read 2 more answers
Do any body know this need help over here
TiliK225 [7]
The answer It’s either A or B
4 0
2 years ago
Read 2 more answers
Geometry help needed<br> Use O for exercises 6-8 6. what is the perimeter of triangle abc
iris [78.8K]

Perimeter of triangle ABC is 20 units.

Solution:

The image for reference is attached below.

Given AE = 2, BD = 5 and CF = 3

Two tangents drawn from an external point to a circle are equal in length.

AD = AE, BF = BD and CE = CF

Therefore, AD = 2, BF = 5 and CE = 3

Perimeter of the triangle = sum of the three sides

Perimeter of triangle ABC = AB + BC + CA

                                           = AD + BD + BF + CF + CE + AE

                                           = 2 + 5 + 5 + 3 + 3 + 2

                                           = 20

Hence, perimeter of triangle ABC is 20 units.

6 0
3 years ago
On a round trip over the same roads, Sophia averaged 24 mi/h going and 30 mi/h coming back. If the whole trip took 13 1/2 hours,
Vaselesa [24]

Answer:

d=rt In this problem we are looking for the distance, but we will have to go about it indirectly. If she's traveling the same exact road going and returning, then the distance traveled both ways is exactly the same. Since d = rt, and d is the same, by the substitution property, if and , then , and . So we need to rt for the trip going, rt for the trip returning and set them equal to each other and solve for t. Going is a rate of 24, and the time is t (since we don't know t), and returning is a rate of 30, and the time is 13 1/3-t. (If the whole trip takes 13 1/3 hours, and t is the time going, then the time returning is the difference between the total time and the going time. That concept is one that baffles most algebra students!). So our r1t1 is 24t, and our r2t2 is 30(13 1/3 - t). Set them equal to each other and that will look like this: That fraction of 40/3 is 13 1/3 made into an improper fraction. Distributing that we will have and 54t = 400. That means that t = 7.407. We have time, and that's great, but we need distance! Go back to one of your equations for distance and sub in t and solve for d. d = 24t, and d = 24(7.407), so d = 177.768 miles.

7 0
2 years ago
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